How does Java form TCP packets from byte arrays?

1
votes

While SocketIn/OutputStreams in Java seem stream based to an API user, TCP packets are packet based. One can write only one byte or an array of bytes. But one could also write more bytes than a TCP packet could carry.

So how does Java form TCP packets from the write methods?

Creates calling write(singleByte) 4 times 4 TCP packets? Or does java join the bytes together?

Does java join and split bytes to form the TCP packets?

1
javasocketsnetworkingtcppacket
The OS is a lot better at handling those things than Java. No need to duplicate functionality by rewriting all that code into the JDK. – Kayaman
@Kayaman So this is handled by the os? Then how do most os's handle it?And why the downvote? – MinecraftShamrock
I didn't downvote you. Most OSes handle it effectively so we don't have to care about it. – Kayaman
Oh alright. Thanks for the info ;) – MinecraftShamrock

1 Answers

1
votes

No, Java, or more precisely the Java Virtual Machine, has no reason to get into these details.

What the JVM does, is that it opens a native Socket just like any native program would. It then allows the Java code to interact with the native socket through the various Java API. This leaves the networking details to the operating system's network stack (TCP/IP implementation).