I used firebug in Firefox to get a xpath for a link that did not have an ID assigned to it. The link is a javascript link with an image as the actual button. I'd like to be able to click this link but it's not working.
The actual xpath is '/html/body/div[2]/div/div/div[3]/div/div/table/tbody/tr[1]/td[2]/form/table/tbody/tr[1]/td/div[1]/div/table/thead/tr[2]/th[1]/a/img'
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
URL = 'http://example.com'
driver.set_window_size(1024, 768)
driver.get(url)
link = driver.find_element_by_xpath(//*[@id="//html/body/div[2]/div/div/div[3]/div/div/table/tbody/tr[1]/td[2]/form/table/tbody/tr[1]/td/div[1]/div/table/thead/tr[2]/th[1]/a/img"])
for link in links:
link.click()
I get the following error:
is either invalid or does not result in a WebElement. The following error occurred:\nInvalidSelectorError: Unable to locate an element with the xpath expression //*[@id=/html/body/div[2]/div/div/div[3]/div/div/table/tbody/tr[1]/td[2]/form/table/tbody/tr[1]/td/div[1]/div/table/thead/tr[2]/th[1]/a/img because of the following error:\n[Exception... "The expression is not a legal expression." code: "12" nsresult: "0x805b0033 (SyntaxError)" location: "<unknown>"]' ; Stacktrace:
<a onclick="if(typeof functionx == 'function'){functionx(document.getElement…,'liststuff','');}return false" href="#">
<img style="border: 0px;" onmouseover="this.src='/add-hover.gif';" onmouseout="this.src='/add.gif';" alt="Add" src="/icon-add.gif"></img>
</a>
<a>
tag may have animg
attribute instead of a nested<img>
tag. If that's true, try changinga/img
toa/@img
at the end of your XPath. – unutbu