Grouping every 3 items in xslt 1.0

Question

I'm having troubles to figure out a way to group items xslt 1.0. I have a source xml similar to the one below:

<client name="client A">
    <project name = "project A1"/>
    <project name = "project A2"/>
    <project name = "project A3"/>
    <project name = "project A4"/>
</client>
<client name="client B">
    <project name = "project B1"/>
    <project name = "project B2"/>
</client>
<client name="client C">
    <project name = "project C1"/>
    <project name = "project C2"/>
    <project name = "project C3"/>
</client>

I'd like to select all projects, sort them and then group every 3 project in one boundle as in the example below:

<boundle>
  <project name="project A1">
  <project name="project A2">
  <project name="project A3">
</boundle>
<boundle>
  <project name="project A4">
  <project name="project B1">
  <project name="project B2">
</boundle>
<boundle>
  <project name="project C1">
  <project name="project C2">
  <project name="project C3">
</boundle>

Currently to do so I'm using to open a boundle tag and close it later. Can you think about any better solution?

Tomalak Tomalak · Accepted Answer · 2010-03-08T09:54:31

No grouping necessary.

<xsl:param name="perGroup" select="3" />

<xsl:variable name="allProjects" select="/client/project" />

<xsl:template match="/">
  <xsl:apply-templates select="$allProjects" mode="counted" />
</xsl:template>

<xsl:template match="project" mode="counted">
  <xsl:if test="position() mod $perGroup = 1">
    <xsl:variable name="pos" select="position()" />
    <boundle>
      <xsl:copy-of select="$allProjects[
        position() &gt;= $pos and position() &lt; ($pos + $perGroup)
      ]" />
    </boundle>
  </xsl:template>
</xsl:template>

Grouping every 3 items in xslt 1.0

2 Answers