I have a hash in which the keys are strings and the values are single-digit numbers; here's a slice of said hash:
'f92a0d43-a230-4bfd-b580-9eac5e0ce6cf' => 7,
'26c4b622-969f-4861-bbab-dd506ea4b00a' => 1,
'afb1f925-4109-4b1d-967f-3958106e0bc3' => 3,
'a099a6dc-0c66-4683-94c3-29d6ef6947fd' => 1,
'e71c4860-224d-4b8d-ae9e-4700e9e65a97' => 2,
I want print the keys in order of descending values. So for the slice listed there, the output would be:
'f92a0d43-a230-4bfd-b580-9eac5e0ce6cf' => 7
'afb1f925-4109-4b1d-967f-3958106e0bc3' => 3
'e71c4860-224d-4b8d-ae9e-4700e9e65a97' => 2
'26c4b622-969f-4861-bbab-dd506ea4b00a' => 1
'a099a6dc-0c66-4683-94c3-29d6ef6947fd' => 1
The order of keys with identical values does not matter. Answers to this question: In Perl, how can I print the key corresponding to the maximum value in a hash? suggest using the sort function; which I have:
my @values = sort { $b <=> $a } values %ID_hash;
What I am having trouble with is actually printing the keys in the order.
I tried:
foreach(@values) {
my $cur = $_;
print "$ID_hash{$cur}\t$cur\n";
}
Which fails because I'm supplying values rather than keys.
I know I can always just print the key/value pairs as a tab-separated file and use the Unix version of sort but I'm sure there's a way to do this with Perl. Any help will be much appreciated.