513
votes

I want to write some pre-defined texts to a file with the following:

text="this is line one\n
this is line two\n
this is line three"

echo -e $text > filename

I'm expecting something like this:

this is line one
this is line two
this is line three

But got this:

this is line one
 this is line two
 this is line three

I'm positive that there is no space after each \n, but how does the extra space come out?

11
I'm not sure but.. how if you just typed text="this is line one\nthis is line two\nthis is line three" in the same one line..? (without any enter)Yohanes Khosiawan 许先汉
Remove the \n on each line, you have already hit newline to move to the new lineMark Setchell
You already given \n.So why you put next line in new line? Simply text="this is line one\nthis is line two\nthis is line three"Jayesh Bhoi
Removing the \n at the end of each line causes the output to all run together on a single line.Jonathan Hartley
Aha: Putting double quotes around the "$text" in the echo line is crucial. Without them, none of the newlines (both literal and '\n') work. With them, they all do.Jonathan Hartley

11 Answers

795
votes

Heredoc sounds more convenient for this purpose. It is used to send multiple commands to a command interpreter program like ex or cat

cat << EndOfMessage
This is line 1.
This is line 2.
Line 3.
EndOfMessage

The string after << indicates where to stop.

To send these lines to a file, use:

cat > $FILE <<- EOM
Line 1.
Line 2.
EOM

You could also store these lines to a variable:

read -r -d '' VAR << EOM
This is line 1.
This is line 2.
Line 3.
EOM

This stores the lines to the variable named VAR.

When printing, remember the quotes around the variable otherwise you won't see the newline characters.

echo "$VAR"

Even better, you can use indentation to make it stand out more in your code. This time just add a - after << to stop the tabs from appearing.

read -r -d '' VAR <<- EOM
    This is line 1.
    This is line 2.
    Line 3.
EOM

But then you must use tabs, not spaces, for indentation in your code.

238
votes

If you're trying to get the string into a variable, another easy way is something like this:

USAGE=$(cat <<-END
    This is line one.
    This is line two.
    This is line three.
END
)

If you indent your string with tabs (i.e., '\t'), the indentation will be stripped out. If you indent with spaces, the indentation will be left in.

NOTE: It is significant that the last closing parenthesis is on another line. The END text must appear on a line by itself.

96
votes

echo adds spaces between the arguments passed to it. $text is subject to variable expansion and word splitting, so your echo command is equivalent to:

echo -e "this" "is" "line" "one\n" "this" "is" "line" "two\n"  ...

You can see that a space will be added before "this". You can either remove the newline characters, and quote $text to preserve the newlines:

text="this is line one
this is line two
this is line three"

echo "$text" > filename

Or you could use printf, which is more robust and portable than echo:

printf "%s\n" "this is line one" "this is line two" "this is line three" > filename

In bash, which supports brace expansion, you could even do:

printf "%s\n" "this is line "{one,two,three} > filename
55
votes

in a bash script the following works:

#!/bin/sh

text="this is line one\nthis is line two\nthis is line three"
echo -e $text > filename

alternatively:

text="this is line one
this is line two
this is line three"
echo "$text" > filename

cat filename gives:

this is line one
this is line two
this is line three
43
votes

I've found more solutions since I wanted to have every line properly indented:

  1. You may use echo:

    echo    "this is line one"   \
        "\n""this is line two"   \
        "\n""this is line three" \
        > filename
    

    It does not work if you put "\n" just before \ on the end of a line.

  2. Alternatively, you can use printf for better portability (I happened to have a lot of problems with echo):

    printf '%s\n' \
        "this is line one"   \
        "this is line two"   \
        "this is line three" \
        > filename
    
  3. Yet another solution might be:

    text=''
    text="${text}this is line one\n"
    text="${text}this is line two\n"
    text="${text}this is line three\n"
    printf "%b" "$text" > filename
    

    or

    text=''
    text+="this is line one\n"
    text+="this is line two\n"
    text+="this is line three\n"
    printf "%b" "$text" > filename
    
  4. Another solution is achieved by mixing printf and sed.

    if something
    then
        printf '%s' '
        this is line one
        this is line two
        this is line three
        ' | sed '1d;$d;s/^    //g'
    fi
    

    It is not easy to refactor code formatted like this as you hardcode the indentation level into the code.

  5. It is possible to use a helper function and some variable substitution tricks:

    unset text
    _() { text="${text}${text+
    }${*}"; }
    # That's an empty line which demonstrates the reasoning behind 
    # the usage of "+" instead of ":+" in the variable substitution 
    # above.
    _ ""
    _ "this is line one"
    _ "this is line two"
    _ "this is line three"
    unset -f _
    printf '%s' "$text"
    
7
votes

The following is my preferred way to assign a multi-line string to a variable (I think it looks nice).

read -r -d '' my_variable << \
_______________________________________________________________________________

String1
String2
String3
...
StringN
_______________________________________________________________________________

The number of underscores is the same (here 80) in both cases.

4
votes

I came hear looking for this answer but also wanted to pipe it to another command. The given answer is correct but if anyone wants to pipe it, you need to pipe it before the multi-line string like this

echo | tee /tmp/pipetest << EndOfMessage
This is line 1.
This is line 2.
Line 3.
EndOfMessage

This will allow you to have a multi line string but also put it in the stdin of a subsequent command.

0
votes

it will work if you put it as below:

AA='first line
\nsecond line 
\nthird line'
echo $AA
output:
first line
second line
third line
0
votes

Just to mention a simple one-line concatenation as it can be useful sometimes.

# for bash

v=" guga "$'\n'"   puga "

# Just for an example.
v2="bar "$'\n'"   foo "$'\n'"$v"

# Let's simplify the previous version of $v2.
n=$'\n'
v3="bar ${n}   foo ${n}$v"

echo "$v3" 

You'll get something like this

bar 
   foo 
 guga 
   puga 

All leading and ending white spaces will be preserved right for

echo "$v3" > filename
0
votes

There are many ways to do it. For me, piping the indented string into sed works nicely.

printf_strip_indent() {
   printf "%s" "$1" | sed "s/^\s*//g" 
}

printf_strip_indent "this is line one
this is line two
this is line three" > "file.txt"

This answer was based on Mateusz Piotrowski's answer but refined a bit.

0
votes

Or keeping text indented with whitespaces:

#!/bin/sh

sed 's/^[[:blank:]]*//' >filename <<EOF
    this is line one
    this is line two
    this is line three
EOF

Same but using a varible:

#!/bin/sh

text="$(sed 's/^[[:blank:]]*//' << whatever
    this is line one
    this is line two
    this is line three
)"

echo "$text" > filename

;-)