How to get the object key when using value in angularFire

Question

I have below code to query the index from users node then pass the index to todos node to get the data I want but it only watching when a child is added so when a child is removed in the index it doesn't update the view.

I have no idea how to get the object key if I use value in the index node. Any idea? or any better way to query mastered data using angularFire?

FirebaseRef.$child(user.uid).$on('child_added', function(a) {
 FirebaseRef.$child('todos/' + a.snapshot.name).$on('value', function(b) {
   $scope.todoList[a.snapshot.name] = b.snapshot;
 });
});

What is FirebaseRef? A Firebase instance or a $firebase/angularFire object? If it's a Firebase object, use .child instead of .$child. Assuming it's a $firebase instance, then it already contains all the contents of todos/. What is the use case we're trying to solve here? It looks like this could be resolved in a simpler manner. — Kato

Tom Maton Tom Maton · Accepted Answer · 2014-05-20T09:45:49

try the following (not tested).

FirebaseRef.$child(user.uid).$on('child_added', function(a) {
 FirebaseRef.$child('todos/' + a.name()).$on('value', function(b) {
   $scope.todoList[a.name()] = b.snapshot;
 });
});

You shouldn't need 'snapshot' in your reference eg a.snapshot.name, you should just reference the object returned in your callback function

How to get the object key when using value in angularFire

1 Answers