I run a lot of long simulations in Matlab, typically taking from a couple of minutes to a couple of hours, so to speed things up I decided to run the simulations simultaneously using a parfor
loop.
arglist = [arg1, arg2, arg3, arg4];
parfor ii = 1:size(arglist, 2)
myfun(arglist(ii));
end
Everything worked just fine, except for one thing: the progress printing. Since each simulation takes a lot of time, I usually print progress using something like
prevlength = 0;
for ii = 1:tot_iter
% Some calculations here
msg = sprintf('Working on %d of %d, %.2f percent done', ii, tot_iter, ii/tot_iter);
fprintf(repmat('\b', 1, prevlength))
fprintf(msg);
prevlength = numel(msg);
end
but, as could be expected, when doing this inside a parfor
loop, you get chaos.
I have googled a lot in search of a solution and have found a bunch of "parfor progress printers" like this one. However, all of them print the progress of the entire parfor
loop instead of showing how far each of the individual iterations have come. Since I only have about 4-8 iterations in the parfor
loop, but each iteration takes about an hour, this approach isn't very helpful to me.
The ideal solution for me would be something that looks like this
Working on 127 of 10000, 1.27 percent done
Working on 259 of 10000, 2.59 percent done
Working on 3895 of 10000, 38.95 percent done
Working on 1347 of 10000, 13.47 percent done
that is, each simulation gets one line showing how far it has run. I'm not sure though if this is possible at all, I can at least not imagine any way to do this.
Another way would be to do something like this
Sim 1: 1.27% Sim 2: 2.59% Sim 3: 38.95% Sim 4: 13.47%
that is, show all the progresses on the same line. To do this, you would need to keep track of what position on the line each simulation is to write on and write there, without erasing the other progresses. I can't figure out how this would be done, is this possible to do?
If there is some other solution to my problem (showing the progress of each individual iteration) that I haven't thought of, I'd be happy to hear about it.
Since this is the first time I ask a question here on SO it is quite possible that there is something that I have missed; if so, please feel free to comment below.
Edit
After receiving this answer, I thought that I should share how I used it to solve my problem since I didn't use it exactly as in the answer, in case someone else encounters the same problem.
Here is a small test program with basically the same structure as my program, making use of the progress bar (parfor_progress
) mentioned in the answer:
function parfor_progress_test()
cpus = feature('numCores');
matlabpool('open', cpus);
cleaner = onCleanup(@mycleaner);
args = [1000, 1000, 1000, 1000];
m = sum(args);
parfor_progress(m);
parfor ii = 1:size(args,2)
my_fun(args(ii));
end
parfor_progress(0);
end
function my_fun(N)
for ii = 1:N
pause(rand*0.01);
parfor_progress;
end
end
function mycleaner
matlabpool close;
fclose all;
end
if mod(ii, 100) == 0; disp(' X ');end
. If I have 1000 iterations if it has printed five X's, then it is halfway done--obviously this assumes a bit of luck because the iterations are randomly selected. So, it's a total hack but it works in a pinch. Frankly in practice I have found it works, even though it has obvious warts. – eric