I am working with R, but need to do a lot of number crunching, which I want to do in fortran. I am relatively new to R and a newbie to fortran... I already have a working R program, which I would like to optimize. I created a Fortran program solving a system of ODE's, which I keep in a subroutine. I additionally use a module called aux.f90 to store the parameters and a function which creates a signal that is fed into the equations. This works as intended and the data is saved in a .txt file.
What I would like to do now is to create an R front-end that tosses the Fortran program the parameters, such as the length of the simulation or the number of steps used in the solution. Then Fortran does the heavy lifting, saves the results in the file and I can use R to visualize the data from the file. See the Fortran code below:
! The auxiliary module contains all parameters
module aux
implicit none
integer,parameter :: n = 2**8 ! number of steps
real(kind=4) :: jout = 0.5 ! for normal metabolism
real(kind=4) :: alp = 4.0 ! factor for growth
real(kind=4) :: bet = 1.0 ! benefit value
real(kind=4) :: etay = 0.1 ! cost value y
real(kind=4) :: etaz = 0.10 ! cost value z
real(kind=4) :: h = 3.0 ! Hill coefficient
real(kind=4) :: Kx = 0.07 ! saturation coefficient
real(kind=4) :: t1 = 0.0, t2 = 30.0 ! start and end point of the simulation
contains ! function f(t) to create a step signal
real(kind=4) function f(t)
implicit none
real(kind=4), intent(in) :: t ! taking time value
real(kind=4) :: tt
!real(kind=4), intent(out) :: s ! giving out the signal
real(kind=4) :: period = 5 ! defining the period length
tt = MODULO(t,period)
! Signal function
if (tt > 0.5*period) then
f = 1
else
f = 0
endif
end function
end module aux
! The program solving the ODE system and giving the output as a fileprogram ffl
program ffl
use aux ! Use module aux
implicit none
integer :: m,j ! iteration variable
real(kind=4), dimension(6) :: b =(/0.0, 0.2, 0.4, 0.6, 0.8, 1.0/) ! expression
real(kind=4) :: dt ! time resolution
real(kind=4), dimension(n) :: t ! time vector
real(kind=4), dimension(4) :: x_new, x_aux, y_new, y_aux, q0 ! vectors
! computing the time vector
dt=(t2-t1)/real(n) ! calculating time resolution
t(1) = t1 ! setting first time value to t1 = 0
do m = 1,n ! filling the time vector
t(m) = t(m-1)+dt
end do
open(unit = 10,file = 'ffl.txt', status = 'unknown')
do j=1,6
k = b(j)
! initial conditions
q0(1) = 0 ! x
q0(2) = k ! y
q0(3) = 0 ! z
q0(4) = 0 ! w
!open(unit = 10,file = 'ffl.txt', status = 'unknown')
x_new = q0 ! set initial conditions
write(10,*)t(1),x_new(1),x_new(2),x_new(3),x_new(4) ! saving data
do m = 2,n
! Solving with a second order method
call derivate(t(m-1),x_new,y_new) ! call the derivate routine
x_aux = x_new + dt*y_new
call derivate(t(m),x_aux,y_aux)
x_new = x_new + 0.5*dt*(y_new+y_aux)
write(10,*)t(m),x_new(1),x_new(2),x_new(3),x_new(4) ! saving data
end do
end do
close(10)
end program ffl
! The subroutine derivate gives the system of ODE's to be solved
subroutine derivate(time,y,z)
use aux ! Use module aux
implicit none
real(kind=4), intent(in) :: time ! input: time vector
real(kind=4), dimension(4), intent(in) :: y ! input: initial conditions vector
real(kind=4), dimension(4), intent(out):: z ! output: results vector
z(1) = f(time)-y(1) !dx/dt
z(2) = k+(1-k)*((1+Kx)*(y(1)**h))/((y(1)**h)+Kx)-y(2) !dy/dt
z(3) = ((1+Kx)*(y(1)**h)/((y(1)**h)+Kx)*((1+Kx)*(y(2)**h))/((y(2)**h)+Kx)-y(3)) !dz/dt
z(4) = f(time)*y(3)-etay*(k+(1-k)*((1+Kx)*(y(1)**h))/((y(1)**h)+Kx)) & !dw/dt
-etaz*(((1+Kx)*(y(1)**h))/((y(1)**h)+Kx)*((1+Kx)*(y(2)**h))/((y(2)**h)+Kx))
end subroutine derivate
I have read the "Writing R extensions" document, but did not find it very helpful...
NOW to the questions: Since R needs a Fortran subroutine, i would like to create a wrapper subroutine in fortran that makes use of my existing files, which I can then call from R. However, i can't find a way to create this wrapper subroutine in the first place. Is it even possible to call an actual program in a subroutine? I couldn't find anything helpful online.