Find physical memory from physical and virtual page numbers and virtual address

Question

I'm having some trouble understanding the direction of a question on the assignment and just need some advice as to how I would calculate the physical memory required in GiB from the following question:

Consider a computer system in which a physical page number is 24 bits, a virtual page number is 52 bits, and a virtual address is 64 bits. What is the maximum amount of physical me mory, in GiB , that this system could have?

What would be the first step to calculating the physical memory?

Answer 1

A virtual page number being 52 bits and a virtual address being 64 bit, there would be;

2 ^ (64 - 52) = 4096 bytes per page.

Since the physical and virtual page size are the same, a 24 bit physical page address would then mean that the physical memory is

(2 ^ 24) * 4096 bytes = 64GiB.