PHP command line version is different from apache

Question

PHP command line on my OS X has the built in Mavericks version: 5.4.24

I have compiled and configured my own php to work with apache, which is version: 5.5.9

The command line version is sitting in /usr/bin and I can rename it to stop it working but don't have a clue where or how to get my compiled (5.5.9) version working through the command line

The 5.5 version has a libphp5.so file that sits under /usr/libexec/apache2

Guys this is a compiled version on a MAC so I did not install it with yum or apt-get or homebrew or ports.

To be clear I am trying to work out how to run the 5.5.9 version from the command line.

Adding COMPOSER-PHP tag as I want to use composer on this Mavericks build which does not support mcrypt without my lovely compiled php, which I can't find!!!!

Here is the configure info:

'./configure' '--prefix=/usr' '--mandir=/usr/share/man' '--infodir=/usr/share/info' '--sysconfdir=/private/etc' '--with-apxs2=/usr/sbin/apxs' '--enable-cli' '--with-config-file-path=/etc' '--with-config-file-scan-dir=/Library/Server/Web/Config/php' '--with-libxml-dir=/usr' '--with-openssl=/usr' '--with-kerberos=/usr' '--with-zlib=/usr' '--enable-bcmath' '--with-bz2=/usr' '--enable-calendar' '--disable-cgi' '--with-curl=/usr' '--enable-dba' '--enable-exif' '--enable-fpm' '--enable-ftp' '--with-gd' '--with-jpeg-dir=/BinaryCache/apache_mod_php/apache_mod_php-87~65/Root/usr/local' '--with-png-dir=/BinaryCache/apache_mod_php/apache_mod_php-87~65/Root/usr/local' '--enable-gd-native-ttf' '--with-icu-dir=/usr' '--with-ldap=/usr' '--with-ldap-sasl=/usr' '--with-libedit=/usr' '--enable-mbstring' '--enable-mbregex' '--with-mysql=mysqlnd' '--with-mysqli=mysqlnd' '--without-pear' '--with-pdo-mysql=mysqlnd' '--with-mysql-sock=/var/mysql/mysql.sock' '--with-readline=/usr' '--enable-shmop' '--with-snmp=/usr' '--enable-soap' '--enable-sockets' '--enable-sysvmsg' '--enable-sysvsem' '--enable-sysvshm' '--with-tidy' '--enable-wddx' '--with-xmlrpc' '--with-iconv-dir=/usr' '--with-xsl=/usr' '--enable-zip' '--with-pcre-regex' '--with-mcrypt' '--with-freetype-dir=/usr/X11R6' '--enable-builtin-freetype'

The Mavericks (5.4.24) version is here:

/usr/bin/php -v

Where is my (5.5.9) version??

.so files:

/Users/lisa/src/php-5.5.9/libs/libphp5.so  
/usr/libexec/apache2/libphp5.so

Well, does not OSX not have a software management? I only know Linux, there you can ask the software management about every package installed, for example what files it contains... Otherwise you can use phps builtin functioon phpinfo() to get information about the engine. Maybe you find usable information about the engine in there. — arkascha
Thanks for responding arkascha, I am not sure about software management on osx, what was the one in Linux called? I did try phpinfo() on both versions but it does not give any clue as to how to get the command line using the 5.5 version...? — Lisa
Different linux distributions use different software management systems, but their purpose and basic function is identical. Anyways, that does not help you. If phpinfo does not offer any insight, then check in your http servers configuration. Somewhere the php executable or library must be configured that is used to interpret php scripts. Be aware that this might only be a library, typically http servers do not use php executables for such tasks these days. — arkascha
I gave that, its: /usr/libexec/apache2/libphp5.so but its an .so file so can't be used from the command line?? — Lisa

DaveyBoy DaveyBoy · Accepted Answer · 2014-04-25T11:14:15

If you compiled it yourself, give us the command you used for that. From there, we can give you some idea as to where it is.

Alternatively, from a command prompt, type

find / -type f -iname '*php*' -print

which will find every file with PHP in the name.

If you're only looking for the libphp5.so file then use

find / -type f -iname 'libphp5.so' -print

It's probably best to run this with higher privileges than normal (sudo it)

PHP command line version is different from apache

1 Answers