I start to read/work on clojure and for that I start to read in parallel 'Programming Clojure' and 'Practical Clojure' books. I saw there one example of how lazy sequence working and for me was very clear in order to understand how lazy-seq work but unfortunately it doesn't work or at least not how I expect.
here is the example:
(defn square[x]
(do
(println "[current.elem=" x "]")
(* x x))
)
(def var-00 (map square '(1 2 3 5 6 4)))
when I call:
var-00
, I expect that no message to print on console(REPL) but I got the follow result:
([current.elem= 1 ][current.elem= 2 ]1 [current.elem= 3 ]4 [current.elem= 5 ]9 [current.elem= 6 ]25 [current.elem= 4 ]36 16)
this mean that the function map was called even I expect to nothing happen since 'var-00' is just a reference to function 'map'; and more awkward from my point of view, if I call:
(nth var-00 2)
I got:
[current.elem= 1 ][current.elem= 2 ][current.elem= 3 ]9
, and if I call again:
(nth var-00 3)
I got:
[current.elem= 1 ][current.elem= 2 ][current.elem= 3 ][current.elem= 5 ]25;
previous elements(1,2,3) was computed again I my opinion those elements should be 'cached' by first call and now only element 5 should be computed. Did I do something wrong or I didn't fully understand how lazy sequence working in clojure ? As a mention I use IntellijIDEA and LaClojure plugin to run the program.
Thanks Sorin.


