I am trying to conditionally suppress a widget from its driver. I basically have logic that if met, should display the widget and if not, should suppress it. The widget loads properties from the current page content item, and based on some properties should display or hide. I've got all the logic working, the only part left is suppressing the actual output.
I've tried returning null from the driver, however this simply outputs an empty widget (with its wrapper). How do I completely remove the widget from view?
Finally, the zone that this widget is placed in should suppress if none of the conditional widgets display.
Is this type of flexibility possible in Orchard? Preferably from my custom module not my theme, I'm trying to separate functionality from styling.
EDIT:
Here is the context of my situation and what I am trying to accomplish. I'm sure there is a much cleaner way to do this within Orchard than how I have naively designed it the first go-around: My client's copywriters tag pages as they see fit (using the Tags module/part). I have created 2 custom content types, "Testimonials" and "Offers", both with tags themselves among other properties [these are managed by a different team of copywriters].
On most "inner pages" of the website (I'm using a layer to determine the appropriate pages), the page's sidebar gets a "Testimonial" widget and a "Offer" widget. These widgets both operate the same, although independently of each other:
They grab the tags of the current page, then pull a random [Testimonial|Offer] that has any matching tags as well. There are 4 cases that can happen given any inner page: a testimonial is displayed and the offer is hidden (testimonial tag matched, offer tag didn't), the testimonial is hidden and the offer is displayed, both the testimonial and offer displays, and finally neither displays. The first 3 use cases are working great, the 4th is what I'm having difficulty with, as the sidebar [zone] still displays even if both widgets do not (returning null from their respective drivers).