if statement - Python: Expected an indented block

3
votes

I thought everything was properly indented here but I am getting an IndentationError: expected an indented block at the else: statement. Am I making an obvious mistake here?

def anti_vowel(text):
    new_string = ""
    vowels = "aeiou"
    for letter in text:
       for vowel in vowels:
           if (lower(letter) == vowel):
               #do nothing
           else:
               #append letter to the new string
               new_string += letter
    return new_string
4
pythonif-statementindentation
For empty blocks you should use pass. - Ashwini Chaudhary
In case you already knew that you had to put something in the if block and thought that you had… a comment isn't a statement. It's simplest to think of it as if comments get removed before the code gets parsed. - abarnert

4 Answers

6
votes

Do nothing translates to using the pass keyword to fill an otherwise empty block (which is not allowed). See the official documentation for more information.

def anti_vowel(text):
    new_string = ""
    vowels = "aeiou"
    for letter in text:
       for vowel in vowels:
           if (lower(letter) == vowel):
               #do nothing
               pass
           else:
               #append letter to the new string
               new_string += letter
    return new_string
7
votes

You need to put something inside the if block. If you don't want to do anything, put pass.

Alternatively, just reverse your condition so you only have one block:

if lower(letter) != vowel:
    new_string += letter

Incidentally, I don't think your code will do what you intend it to do, but that's an issue for another question.

0
votes

You can't do this. 

if (lower(letter) == vowel):
    #do nothing

Try: 

if (lower(letter) == vowel):
    #do nothing
    pass
-1
votes

This can be caused by mixing tabs and spaces. However, this is probably caused by having nothing inside your if statement. You can use "pass" as a placeholder (see example below).

    if condition:
        pass

Information on pass: http://docs.python.org/release/2.5.2/ref/pass.html