symfony jquery ajax json error

Question

my controller:

jjgp_bisa_bis_crea_mensaje: pattern: /creamensaje defaults: { _controller: JJGPBisaBisBundle:Default:creamensaje }

my Action function

public function creamensajeAction() {

    $request = Request::createFromGlobals();

    $usermail = $request->request->get('usermail');
    $mensaje = $request->request->get('mensaje');
    $leido = $request->request->get('leido');
    $fecha = date("d-m-Y H:i:s");

    $em = $this->getDoctrine()->getManager();
    $mensajes = $em->getRepository('JJGPBisaBisBundle:Mensajes')->CrearMensajes($usermail, $mensaje, $fecha, $leido);
    $em = $this->getDoctrine()->getManager();
    $em->persist($mensajes);
    $em->flush();

    // response test

    $return['usermail'] = 'a';
    $return['mensaje'] = "b";
    $return['leido'] = "c";

    return json_encode($return);
}

my jquery:

$.ajax({
    type: 'POST',
    url: '{{ path('jjgp_bisa_bis_crea_mensaje') }}',
    dataType: 'json',
    data: {    // test vars only
        usermail: "email",
        mensaje: $txt_enviar ,
        leido: "no"
    },
    success: function(data) {
        alert(data.msg);
    },
    error: function(XMLHttpRequest, textStatus, errorThrown) {
        alert("error"); // always jump here!! that's the problem!
    }
});

All of this seems work ok, I can see how the database is growing up and works fine, but jquery always alerts me error function, and I don't know why!

I think it can be the controller path but I am not sure

Sehael Sehael · Accepted Answer · 2014-01-23T02:58:03

Your action has to return some sort of Response object. In your case, you can use a JsonResponse. include this statement:

use Symfony\Component\HttpFoundation\JsonResponse;

And the you can replace this line

return json_encode($return);

with this:

return new JsonResponse($return);

You may also want to look at what error is thrown. Without the error message, it is kinda hard to see exactly what the problem is.

symfony jquery ajax json error

1 Answers