I tried to create a Java program using Hibernate 4.1.6 and Spring 3.0.5. When i ran my app throwing NULLPOINT EXCEPTION. Anyone help me, please,
SpringBeans.xml:
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
<!-- Database Configuration --> <import resource="config/spring/DataSource.xml"/> <import resource="config/spring/HibernateSessionFactory.xml"/> <!-- Beans Declaration --> <import resource="config/spring/UserBeans.xml"/>
2. HibernateSessionFactory.xml
<property name="dataSource"> <ref bean="dataSource"/> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> <property name="mappingResources"> <list> <value>com/model/TblUser.hbm.xml</value> </list> </property>
DataSource.xml
WEB-INF/classes/config/database/properties/database.properties
database.properties
jdbc.driverClassName=com.mysql.jdbc.Driver jdbc.url=jdbc:mysql:localhost:3306/auction_nms jdbc.username=root jdbc.password=root
UserBeans.xml
<!-- User business object -->
UserDaoImpl .java
public class UserDaoImpl implements UserDao { @Autowired SessionFactory sessionFactory;
/* * @see com.dao.UserDao#save(com.model.TblUser) */ @Override public void save(TblUser user) { sessionFactory.getCurrentSession().save(user); }
7.App.java
public class App {
// get log4j handler
private static final Logger logger = Logger.getLogger(App.class);
static TblUser user = new TblUser(2, "2", "2");
public static void main(String[] args) {
try {
UserDao userDao = new UserDaoImpl();
userDao.save(user);
} catch (Exception e) {
System.err.`enter code here`println(e);
} finally {
if (logger.isDebugEnabled()) {
logger.debug(user);
}
}
}
}
Thank you very much!!!
new
operator. If you create it withnew
, Spring cannot inject SessionFactory and end up with NPE. – user1516873