Let's say I have a string: "10/12/13" and "10/15/13", how can I convert them into date objects so that I can compare the dates? For example to see which date is before or after.
7 Answers
51
votes
Use datetime.datetime.strptime:
>>> from datetime import datetime as dt
>>> a = dt.strptime("10/12/13", "%m/%d/%y")
>>> b = dt.strptime("10/15/13", "%m/%d/%y")
>>> a > b
False
>>> a < b
True
>>>
13
votes
If you like to use the dateutil and its parser:
from dateutil.parser import parse
date1 = parse('10/12/13')
date2 = parse('10/15/13')
print date1 - date2
print date2 > date2
11
votes
Here's one solution using datetime.datetime.strptime:
>>> date1 = datetime.datetime.strptime('10/12/13', '%m/%d/%y')
>>> date2 = datetime.datetime.strptime('10/15/13', '%m/%d/%y')
>>> date1 < date2
True
>>> date1 > date2
False
3
votes
Use datetime.datetime.strptime.
from datetime import datetime
a = datetime.strptime('10/12/13', '%m/%d/%y')
b = datetime.strptime('10/15/13', '%m/%d/%y')
print 'a' if a > b else 'b' if b > a else 'tie'
0
votes
0
votes
I know this post is 7 years old, but wanted to say that you can compare two date strings without converting them to dates
>>> "10/12/13" > "10/15/13"
False
>>> "10/12/13" < "10/15/13"
True
>>> "10/12/13" == "10/15/13"
False
If there is anything wrong with this approach I would love for someone to tell me.
dateutil- gongzhitaao10/15/13? - aIKid