How to identify cxf web service end point

Question

I am trying to creating web service using wsdl first approach and CXF. I am able to generate java file from wsdl and deploy the war file to tomcat server. However, I don't see any soapaction in the generated file. How do I identify the end point url for this web service?

thanks,

Dawid Pytel Dawid Pytel · Accepted Answer · 2013-10-26T18:00:31

Usually in CXF you use Spring configuration to configure endpoint, as described in JAX-WS Configuration. Usually address is relative, e.g.

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:jaxws="http://cxf.apache.org/jaxws"
    xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd">

    <jaxws:endpoint id="classImpl"
        implementor="org.apache.cxf.jaxws.service.Hello"
        address="/helloService"/>

</beans>

Address is local to you web app context root.

Assuming that name of you web application is SomeWebApp and the server is available at localhost:8080 then web service should be published at http://localhost:8080/SomeWebApp/helloService. You can test it retrieving WSDL at: http://localhost:8080/SomeWebApp/helloService?wsdl. This URL can be used to create SOAP UI project (the tool that I really recommend for exploring and testing SOAP services).

If you don't use Spring to configure endpoint or you still can't access web service please provide more details about your configuration.

How to identify cxf web service end point

1 Answers