I am trying to convert a hex value to an int so I can create a new color drawable. I'm not sure if this is possible, but according to the documentation, it should. It plainly asks for
public ColorDrawable (int color)
Added in API level 1 Creates a new ColorDrawable with the specified color.
Parameters color The color to draw.
So, my code isn't working because I'm getting an Invalid int: "FF6666" error. Any ideas?
int decode = Integer.decode("FF6666");
ColorDrawable colorDrawable = new ColorDrawable(decode);