In the Old Days (pre-ANSI), predefining symbols such as unix
and vax
was a way to allow code to detect at compile time what system it was being compiled for. There was no official language standard back then (beyond the reference material at the back of the first edition of K&R), and C code of any complexity was typically a complex maze of #ifdef
s to allow for differences between systems. These macro definitions were generally set by the compiler itself, not defined in a library header file. Since there were no real rules about which identifiers could be used by the implementation and which were reserved for programmers, compiler writers felt free to use simple names like unix
and assumed that programmers would simply avoid using those names for their own purposes.
The 1989 ANSI C standard introduced rules restricting what symbols an implementation could legally predefine. A macro predefined by the compiler could only have a name starting with two underscores, or with an underscore followed by an uppercase letter, leaving programmers free to use identifiers not matching that pattern and not used in the standard library.
As a result, any compiler that predefines unix
or linux
is non-conforming, since it will fail to compile perfectly legal code that uses something like int linux = 5;
.
As it happens, gcc is non-conforming by default -- but it can be made to conform (reasonably well) with the right command-line options:
gcc -std=c90 -pedantic ... # or -std=c89 or -ansi
gcc -std=c99 -pedantic
gcc -std=c11 -pedantic
See the gcc manual for more details.
gcc will be phasing out these definitions in future releases, so you shouldn't write code that depends on them. If your program needs to know whether it's being compiled for a Linux target or not it can check whether __linux__
is defined (assuming you're using gcc or a compiler that's compatible with it). See the GNU C preprocessor manual for more information.
A largely irrelevant aside: the "Best One Liner" winner of the 1987 International Obfuscated C Code Contest, by David Korn (yes, the author of the Korn Shell) took advantage of the predefined unix
macro:
main() { printf(&unix["\021%six\012\0"],(unix)["have"]+"fun"-0x60);}
It prints "unix"
, but for reasons that have absolutely nothing to do with the spelling of the macro name.
#undef linux
, or perhaps using a different variable? I think the constantlinux
is used to test for operating systems e.g. if you're designing a cross-platform application and need to know exactly which API to use (windows, mac, linux, BSD, etc). It's not in stdio.h, but it is still defined if the kernel is linux. The same code should not produce an error in Windows, but using something like windows or WINDOWS as the variable probably will, and vice versa – Braden Bestlinux
is number one. – EsmaeelE