C++ passing an object to a function, the operator= is not called

0
votes

So here is the code snippet:

class MyClass { public: MyClass(char chIn) { std::cout << "Constructor!" << std::endl; }

MyClass & operator= (char chIn) { std::cout << "Assigment operator!" << std::endl; } } ;

void Func(MyClass objIn) { return; }

int _tmain(int argc, _TCHAR* argv[]) { Func('T'); system("PAUSE"); return 0; }

In the upper example the constructor of the object is called!!!! Why is this behavior? Shouldn't the assigment operator be called? Because we're assigning a value to the function parameter, aren't we?

1
visual-c++

1 Answers

1
votes

operator= invoked for already existent object otherwise constructor(or copy constructor) is used to create needed instance