XSLT Parsing error when using Umbraco GetMedia

Question

I am trying to retrieve the url to an image using the GetMedia mediapicker.

The code below works fine:

<xsl:for-each select="umbraco.library:GetXmlNodeById(1123)/* [@isDoc]">
  <article>
     <img width="1822" height="600">
       <xsl:attribute name="src">
         <xsl:value-of select="umbraco.library:GetMedia(1139, 0)/umbracoFile" />
       </xsl:attribute>
     </img>
     <div class="contents">
        <h1>
          <xsl:value-of select="bannerHeading1"/>
        </h1>
      </div>
  </article>
</xsl:for-each>

However, if I replace the key line with this:

<xsl:value-of select="umbraco.library:GetMedia(bannerImage, 0)/umbracoFile" />

I get a parsing error with the exception being an OverflowException (Value was either too large or too small for an Int32), which suggests that it's not the 1139 that is being passed in.

Is there a way I can pass in the property I want? The value of "bannerImage" is 1139 as I want it to be?

Thanks for any help.

Further: This is the XML structure being returned by GetXMLNodeById:

<?xml version="1.0" encoding="utf-8" ?>
<HomepageBanner id="1141" parentID="1123" level="3" writerID="0" creatorID="0" nodeType="1124" template="1125" sortOrder="0" createDate="2013-08-12T15:53:48" updateDate="2013-08-12T15:54:18" nodeName="Members" urlName="members" writerName="admin" creatorName="admin" path="-1,1065,1123,1141" isDoc="">
  <bannerImage>1139</bannerImage>
  <bannerHeading1>Members Area</bannerHeading1>
  <bannerHeading2>..the place for all your needs</bannerHeading2>
</HomepageBanner>

Please include what umbraco.library:GetXmlNodeById(1123) returns. — Tomalak
I meant the actual XML structure that function call returns, pasted as XML. — Tomalak
Don't tell us "I get a parsing error." Tell us what the error is. You might not understand it, but that doesn't mean no-one else does. — Michael Kay
@Tomalak, MichaelKay : I've added notes. Thanks for looking at this. — Ste
Have you double-checked your expectations? What does <xsl:value-of select="bannerImage" /> output when placed above the <img>? Apart from that, the XSLT is syntactically valid. An error would happen as a run-time error in umbraco.library:GetMedia(), which is why I assume you are not passing the correct arguments for that function. — Tomalak

Ste Ste · Accepted Answer · 2013-08-13T14:25:58

For anyone else trying to get an image from an item in a content folder, this is how I got it to work:

<xsl:for-each select="umbraco.library:GetXmlNodeById(1123)/* [@isDoc]">
  <article>
    <!-- Store the ID -->
    <xsl:variable name="mediaId" select="bannerImage" />
      <!-- Check the ID is numeric -->
      <xsl:if test="number($mediaId) &gt; 0">
        <xsl:variable name="mediaNode" select="umbraco.library:GetMedia($mediaId, false())" />
        <xsl:if test="string-length($mediaNode/umbracoFile) &gt; 0">
          <img src="{$mediaNode/umbracoFile}" width="1822" height="600" />
          <div class="contents">
            <h1>
              <xsl:value-of select="bannerHeading1"/>
            </h1>
          </div>
        </xsl:if>
      </xsl:if>
    </article>
</xsl:for-each>

You first need to check that the value is numeric and then, the bit that was failing me, you need to add the "/umbracoFile" part to your media node variable.

Thanks to the contributors who helped me in the right direction.

XSLT Parsing error when using Umbraco GetMedia

1 Answers