Error unzipping a file in cmd (using 7z in Windows)

10
votes

I am attempting to use 7 Zip through the command line. As you can see below, using the command 7z l lists the 3 files in the target zip file.

C:\Users\User1\Downloads>7z l recording_20130731180507.zip

--
Path = recording_20130731180507.zip
Type = zip
Physical Size = 311686

   Date      Time    Attr         Size   Compressed  Name
------------------- ----- ------------ ------------  ------------------------
2013-07-31 18:05:06 .....          655          655  SD_DISK\20130731\18\2013073
1_180505_A4BC_00408CC2B40B\recording.xml
2013-07-31 18:05:06 .....       309752       309752  SD_DISK\20130731\18\2013073
1_180505_A4BC_00408CC2B40B\20130731_18\20130731_180505_59EB_00408CC2B40B.mkv
2013-07-31 18:05:06 .....          279          279  SD_DISK\20130731\18\2013073
1_180505_A4BC_00408CC2B40B\20130731_18\20130731_180505_59EB_00408CC2B40B.xml
------------------- ----- ------------ ------------  ------------------------
                                310686       310686  3 files, 0 folders

However, when I attempt to actually unzip the file, I get a "no files to process error". I've never tried unzipping from cmd before. Do I have to try to dig into the zip file to extract those 3 files? 

C:\Users\User1\Downloads>7z e recording_20130731180507.zip o-C:\users\User1\do
cuments\folder1\test


No files to process

Files: 0
Size:       0
Compressed: 311686
1
cmd7zip

1 Answers

12
votes

The option is -o, not o-. Run the command like this:

7z e recording_20130731180507.zip -o"C:\users\User1\documents\folder1\test"