One of my coworkers was using the builtin max function (on Python 2.7), and he found a weird behavior.
By mistake, instead of using the keyword argument key (as in key=lambda n: n) to pre-sort the list passed as a parameter, he did:
>>> max([1,2,3,3], lambda n : n)
[1, 2, 3, 3]
He was doing what in the documentation is explained as:
If two or more positional arguments are provided, the largest of the positional arguments is returned., so now I'm curious about why this happens:
>>> (lambda n:n) < []
True
>>> def hello():
... pass
...
>>> hello < []
True
>>> len(hello)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: object of type 'function' has no len()
I know it's not a big deal, but I'd appreciate if any of the stackoverflowers could explain how those comparisons are internally made (or point me into a direction where I can find that information). :-)
Thank you in advance!
lambda n: nto deciding to compare against function objects? :) - Jon Clements