I think that the problem in the third command is the requested size itself:
-
in the first command both dimensions are divided by 4:
320/4=80
and 444/4=111
-
in the second command both dimensions are divided by 2:
320/2=160
and 444/2=222
444 and 320 have only two common divisors: 2 and 4. You already used these divisors in your first two commands, so any other (width, height) couple will give you a slightly different aspect ratio: it is impossible to obtain the same exact aspect ratio fixing 290.
In fact while your original image has an aspect ratio of 1.3875
, with a 290x403 image you would obtain an aspect ratio of 1,389655172
and with a 290x402 image you would get a 1,386206897
ratio: fixing 290 there is no other dimension's value that can give you the desired aspect ratio.
In general however Imagemagick always tries to preserve the aspect ratio of the image, as you can read in Imagemagick documentation:
The argument to the resize operator is the area into which the image
should be fitted. This area is not the final size of the image but the
maximum sizes for the image. that is because IM tries to preserve the
aspect ratio of the image more than the final (unless a '!' flag is
given), but at least one (if not both) of the final dimensions should
match the argument given image. So let me be clear... Resize will fit
the image into the requested size. It does NOT fill, the requested box
size.
For further reference see here