The following grammar has left recursion.
X is the start simbol.
X -> Xa | Zb
Z -> Zc | d | Xa
How to remove it? Please explain it step by step.
-- remove Z left recursion--
X -> Xa | Zb
Z -> dZ' | XaZ'
Z' -> cZ' | empty
--next remove Z --
X -> Xa | dZ'b | XaZ'b
Z' -> cZ' | empty
--next factorize X--
X -> XaX' | dZ'b
X'-> Z'b | empty
Z'-> cZ' | empty
--next remove X recursion--
X -> dZ'bX''
X'' -> a X'X'' | empty
X' -> Z'b | empty
Z' -> cZ' | empty
Z
thenX
. – Grijesh Chauhan