This is my makefile:
all:ll
ll:ll.c
gcc -c -Wall -Werror -02 c.c ll.c -o ll $@ $<
clean :
\rm -fr ll
When I try to make clean
or make make
, I get this error:
:makefile:4: *** missing separator. Stop.
How can I fix it?
This is my makefile:
all:ll
ll:ll.c
gcc -c -Wall -Werror -02 c.c ll.c -o ll $@ $<
clean :
\rm -fr ll
When I try to make clean
or make make
, I get this error:
:makefile:4: *** missing separator. Stop.
How can I fix it?
make has a very stupid relationship with tabs. All actions of every rule are identified by tabs. And, no, four spaces don't make a tab. Only a tab makes a tab.
To check, I use the command cat -e -t -v makefile_name
.
It shows the presence of tabs with ^I
and line endings with $
. Both are vital to ensure that dependencies end properly and tabs mark the action for the rules so that they are easily identifiable to the make utility.
Example:
Kaizen ~/so_test $ cat -e -t -v mk.t
all:ll$ ## here the $ is end of line ...
$
ll:ll.c $
^Igcc -c -Wall -Werror -02 c.c ll.c -o ll $@ $<$
## the ^I above means a tab was there before the action part, so this line is ok .
$
clean :$
\rm -fr ll$
## see here there is no ^I which means , tab is not present ....
## in this case you need to open the file again and edit/ensure a tab
## starts the action part
Using .editorconfig
to fix the tabs automagically:
root = true
[*]
charset = utf-8
end_of_line = lf
insert_final_newline = true
indent_style = space
indent_size = 4
[Makefile]
indent_style = tab
Its pretty old question but still I would like say about one more option using vi/vim
editor to visualize the tabs. If you have vi/vim
installed then open a Makefile
(e.g. vim Makefile
) and enter :set list
. This will show number of tabs inserted as below,
%-linux: force$
^I@if [ "$(GCC_VERSION)" = "2.96" ] ; then \$
^I^Iecho ===== Generating build tree for legacy $@ architecture =====; \$
^I^I$(CONFIGURE) $(CWD) $@ legacy; \$
^Ielse \$
^I^Iecho ===== Generating build tree for $@ architecture =====; \$
^I^I$(CONFIGURE) $(CWD) $@; \$
^Ifi$
^Icd build-$@;make$
makefile syntax can be quirky
if you want a line of code to be interpreted as make
code it must only be indented with spaces.
if you want a line of code to be interpreted as bash
code it must only be indented with tabs
sometask:
ifeq($FOO,bar) // this is make code. only spaces
echo "foobar" // this is bash code. only tabs
endif // again, this is make code. only spaces
technically its the leading indentation that dictates the interpreter.
If anyone of you are using a product from Intellij, the solution for this it's the following:
Other File Types
.Use tab character
and be careful, Tab size
and Indent
values must be 4.