I'm kind of new with PDO and currently developing the API call that returns search results. How do I set a prepare statement if there are 2 optional parameters for the search query?
$app->get('/get/search', function () {
$sql = 'SELECT * FROM user WHERE name LIKE :name AND city = :city AND gender = :gender';
try {
$stmt = cnn()->prepare($sql);
$stmt->bindParam(':name', '%'.$_GET['name'].'%', PDO::PARAM_STR);
$stmt->bindParam(':city', '%'.$_GET['city'].'%', PDO::PARAM_STR);
$stmt->bindParam(':gender', $_GET['gender'], PDO::PARAM_INT);
$stmt->execute();
if($data = $stmt->fetchAll()) {
echo json_encode($data);
} else {
echo json_encode(array('error' => 'no records found');
}
} catch(PDOException $e) {
echo json_encode(array('error' => $e->getMessage()));
}
}
The issue here, is that both $_GET['city'] and $_GET['gender'] are optional. If I try to run the code above, it will asume that any empty variable should match an empty value in the column as well; in the other hand, if I do something like this:
if($_GET['gender']) $stmt->bindParam(':gender', $_GET['gender'], PDO::PARAM_INT);
...it will return this error: "SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens"
So, what's the solution if I want to keep the prepared sql statement for optional parameters? Thanks!
Update
This is the solution based on the accepted answer and some comments (by deceze and bill-karwin):
if($_GET['name']) $where[] = 'name LIKE :name';
if($_GET['city']) $where[] = 'city LIKE :city';
if(isset($_GET['gender'])) $where[] = 'gender = :gender';
if(count($where)) {
$sql = 'SELECT * FROM user WHERE '.implode(' AND ',$where);
$stmt = cnn()->prepare($sql);
$name = '%'.$_GET['name'].'%';
if($_GET['name']) $stmt->bindValue(':name', '%'.$_GET['name'].'%', PDO::PARAM_STR);
$city = '%'.$_GET['city'].'%';
if($_GET['city']) $stmt->bindParam(':city', $city, PDO::PARAM_STR);
if(isset($_GET['gender'])) $stmt->bindParam(':gender', $_GET['gender'], PDO::PARAM_BOOL);
$stmt->execute();
if($data = $stmt->fetchAll()) {
echo json_encode($data);
}
}