I'm experimenting with this dup2 command in linux. I've written a code as follows:
#include <stdio.h>
#include <unistd.h>
#include <string.h>
int main()
{
int pipe1_ends[2];
int pipe2_ends[2];
char string[] = "this \n is \n not \n sorted";
char buffer[100];
pid_t pid;
pipe(pipe1_ends);
pipe(pipe2_ends);
pid = fork();
if(pid > 0) { /* parent */
close(pipe1_ends[0]);
close(pipe2_ends[1]);
write(pipe1_ends[1],string,strlen(string));
read(pipe2_ends[0], buffer, 100);
printf("%s",buffer);
return 0;
}
if(pid == 0) { /* child */
close(pipe1_ends[1]);
close(pipe2_ends[0]);
dup2(pipe1_ends[0], 0);
dup2(pipe2_ends[1],1);
char *args[2];
args[0] = "/usr/bin/sort";
args[1] = NULL;
execv("/usr/bin/sort",args);
}
return 0;
}
I expect this program to behave as follows: It should fork a child and replace its image with sort process. And since the stdin and stdout are replaced with dup2 command, I expect sort to read input from the pipe and write the output into the other pipe which is printed by the parent. But the sort program doesn't seem to be reading any input. If no commandline argument is given, sort reads it from the stdin right? Can someone help me with this problem, please.
Many thanks!