The method Geocoder.getFromLocationName()
throws the exception Service not available
on Android 4.1, even if GooglePlayServicesUtil.isGooglePlayServicesAvailable()
returns SUCCESS
and Geocoder.isPresent()
returns true
.
Is there any official example for geocoding in the new Google Maps v2 API?
1
votes
I found a workaround for this: reboot the device. But it's not a solution...
– Umberto
I'm still finding a way to solve this bug. Any ideas?
– Umberto
Any ideas? Seems the Geocoder doesn't work on Android 4, with Google Maps V2
– Umberto
2 Answers
3
votes
Geocoder
is not related to Google Maps Android API v2.
You may want to use Google Geocoding API directly instead of Geocoder
, which gives you limited amount of data and might be affected by device or Android version specific problems.
2
votes
try this .....
public JSONObject getLocationFormGoogle(String placesName) {
HttpGet httpGet = new HttpGet("http://maps.google.com/maps/api/geocode/json?address=" +placesName+"&ka&sensor=false");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
StringBuilder stringBuilder = new StringBuilder();
try {
response = client.execute(httpGet);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
} catch (JSONException e) {
e.printStackTrace();
}
return jsonObject;
}
public LatLng getLatLng(JSONObject jsonObject) {
Double lon = new Double(0);
Double lat = new Double(0);
try {
lon = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
lat = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return new LatLng(lat,lon);
}
LatLng Source =getLatLng(getLocationFormGoogle(placesName));