How to select the nth row in a SQL database table?

Question

I'm interested in learning some (ideally) database agnostic ways of selecting the nth row from a database table. It would also be interesting to see how this can be achieved using the native functionality of the following databases:

• SQL Server
• MySQL
• PostgreSQL
• SQLite
• Oracle

I am currently doing something like the following in SQL Server 2005, but I'd be interested in seeing other's more agnostic approaches:

WITH Ordered AS (
SELECT ROW_NUMBER() OVER (ORDER BY OrderID) AS RowNumber, OrderID, OrderDate
FROM Orders)
SELECT *
FROM Ordered
WHERE RowNumber = 1000000

Credit for the above SQL: Firoz Ansari's Weblog

Update: See Troels Arvin's answer regarding the SQL standard. Troels, have you got any links we can cite?

Answer 1

There are ways of doing this in optional parts of the standard, but a lot of databases support their own way of doing it.

A really good site that talks about this and other things is http://troels.arvin.dk/db/rdbms/#select-limit.

Basically, PostgreSQL and MySQL supports the non-standard:

SELECT...
LIMIT y OFFSET x 

Oracle, DB2 and MSSQL supports the standard windowing functions:

SELECT * FROM (
  SELECT
    ROW_NUMBER() OVER (ORDER BY key ASC) AS rownumber,
    columns
  FROM tablename
) AS foo
WHERE rownumber <= n

(which I just copied from the site linked above since I never use those DBs)

Update: As of PostgreSQL 8.4 the standard windowing functions are supported, so expect the second example to work for PostgreSQL as well.

Update: SQLite added window functions support in version 3.25.0 on 2018-09-15 so both forms also work in SQLite.

Answer 2

PostgreSQL supports windowing functions as defined by the SQL standard, but they're awkward, so most people use (the non-standard) LIMIT / OFFSET:

SELECT
    *
FROM
    mytable
ORDER BY
    somefield
LIMIT 1 OFFSET 20;

This example selects the 21st row. OFFSET 20 is telling Postgres to skip the first 20 records. If you don't specify an ORDER BY clause, there's no guarantee which record you will get back, which is rarely useful.

Answer 3

I'm not sure about any of the rest, but I know SQLite and MySQL don't have any "default" row ordering. In those two dialects, at least, the following snippet grabs the 15th entry from the_table, sorting by the date/time it was added:

SELECT * FROM the_table ORDER BY added DESC LIMIT 1,15

(of course, you'd need to have an added DATETIME field, and set it to the date/time that entry was added...)

Answer 4

SQL 2005 and above has this feature built-in. Use the ROW_NUMBER() function. It is excellent for web-pages with a << Prev and Next >> style browsing:

Syntax:

SELECT
    *
FROM
    (
        SELECT
            ROW_NUMBER () OVER (ORDER BY MyColumnToOrderBy) AS RowNum,
            *
        FROM
            Table_1
    ) sub
WHERE
    RowNum = 23

Answer 5

I suspect this is wildly inefficient but is quite a simple approach, which worked on a small dataset that I tried it on.

select top 1 field
from table
where field in (select top 5 field from table order by field asc)
order by field desc

This would get the 5th item, change the second top number to get a different nth item

SQL server only (I think) but should work on older versions that do not support ROW_NUMBER().

Answer 6

Verify it on SQL Server:

Select top 10 * From emp 
EXCEPT
Select top 9 * From emp

This will give you 10th ROW of emp table!

Answer 7

1 small change: n-1 instead of n.

select *
from thetable
limit n-1, 1

Answer 8

Contrary to what some of the answers claim, the SQL standard is not silent regarding this subject.

Since SQL:2003, you have been able to use "window functions" to skip rows and limit result sets.

And in SQL:2008, a slightly simpler approach had been added, using
OFFSET skip ROWS FETCH FIRST n ROWS ONLY

Personally, I don't think that SQL:2008's addition was really needed, so if I were ISO, I would have kept it out of an already rather large standard.

Answer 9

SQL SERVER

---

Select n' th record from top

SELECT * FROM (
SELECT 
ID, NAME, ROW_NUMBER() OVER(ORDER BY ID) AS ROW
FROM TABLE 
) AS TMP 
WHERE ROW = n

select n' th record from bottom

SELECT * FROM (
SELECT 
ID, NAME, ROW_NUMBER() OVER(ORDER BY ID DESC) AS ROW
FROM TABLE 
) AS TMP 
WHERE ROW = n

Answer 10

When we used to work in MSSQL 2000, we did what we called the "triple-flip":

EDITED

DECLARE @InnerPageSize int
DECLARE @OuterPageSize int
DECLARE @Count int

SELECT @Count = COUNT(<column>) FROM <TABLE>
SET @InnerPageSize = @PageNum * @PageSize
SET @OuterPageSize = @Count - ((@PageNum - 1) * @PageSize)

IF (@OuterPageSize < 0)
    SET @OuterPageSize = 0
ELSE IF (@OuterPageSize > @PageSize)
    SET @OuterPageSize = @PageSize

DECLARE @sql NVARCHAR(8000)

SET @sql = 'SELECT * FROM
(
    SELECT TOP ' + CAST(@OuterPageSize AS nvarchar(5)) + ' * FROM
    (
        SELECT TOP ' + CAST(@InnerPageSize AS nvarchar(5)) + ' * FROM <TABLE> ORDER BY <column> ASC
    ) AS t1 ORDER BY <column> DESC
) AS t2 ORDER BY <column> ASC'

PRINT @sql
EXECUTE sp_executesql @sql

It wasn't elegant, and it wasn't fast, but it worked.

Answer 11

In Oracle 12c, You may use OFFSET..FETCH..ROWS option with ORDER BY

For example, to get the 3rd record from top:

SELECT * 
FROM   sometable
ORDER BY column_name
OFFSET 2 ROWS FETCH NEXT 1 ROWS ONLY;

Answer 12

Oracle:

select * from (select foo from bar order by foo) where ROWNUM = x

Answer 13

Here is a fast solution of your confusion.

SELECT * FROM table ORDER BY `id` DESC LIMIT N, 1

Here You may get Last row by Filling N=0, Second last by N=1, Fourth Last By Filling N=3 and so on.

This is very common question over the interview and this is Very simple ans of it.

Further If you want Amount, ID or some Numeric Sorting Order than u may go for CAST function in MySQL.

SELECT DISTINCT (`amount`) FROM cart ORDER BY CAST( `amount` AS SIGNED ) DESC LIMIT 4 , 1

Here By filling N = 4 You will be able to get Fifth Last Record of Highest Amount from CART table. You can fit your field and table name and come up with solution.

Answer 14

ADD:

LIMIT n,1

That will limit the results to one result starting at result n.

Answer 15

For example, if you want to select every 10th row in MSSQL, you can use;

SELECT * FROM (
  SELECT
    ROW_NUMBER() OVER (ORDER BY ColumnName1 ASC) AS rownumber, ColumnName1, ColumnName2
  FROM TableName
) AS foo
WHERE rownumber % 10 = 0

Just take the MOD and change number 10 here any number you want.

Answer 16

For SQL Server, a generic way to go by row number is as such:

SET ROWCOUNT @row --@row = the row number you wish to work on.

For Example:

set rowcount 20   --sets row to 20th row

select meat, cheese from dbo.sandwich --select columns from table at 20th row

set rowcount 0   --sets rowcount back to all rows

This will return the 20th row's information. Be sure to put in the rowcount 0 afterward.

Answer 17

Here's a generic version of a sproc I recently wrote for Oracle that allows for dynamic paging/sorting - HTH

-- p_LowerBound = first row # in the returned set; if second page of 10 rows,
--                this would be 11 (-1 for unbounded/not set)
-- p_UpperBound = last row # in the returned set; if second page of 10 rows,
--                this would be 20 (-1 for unbounded/not set)

OPEN o_Cursor FOR
SELECT * FROM (
SELECT
    Column1,
    Column2
    rownum AS rn
FROM
(
    SELECT
        tbl.Column1,
        tbl.column2
    FROM MyTable tbl
    WHERE
        tbl.Column1 = p_PKParam OR
        tbl.Column1 = -1
    ORDER BY
        DECODE(p_sortOrder, 'A', DECODE(p_sortColumn, 1, Column1, 'X'),'X'),
        DECODE(p_sortOrder, 'D', DECODE(p_sortColumn, 1, Column1, 'X'),'X') DESC,
        DECODE(p_sortOrder, 'A', DECODE(p_sortColumn, 2, Column2, sysdate),sysdate),
        DECODE(p_sortOrder, 'D', DECODE(p_sortColumn, 2, Column2, sysdate),sysdate) DESC
))
WHERE
    (rn >= p_lowerBound OR p_lowerBound = -1) AND
    (rn <= p_upperBound OR p_upperBound = -1);

Answer 18

But really, isn't all this really just parlor tricks for good database design in the first place? The few times I needed functionality like this it was for a simple one off query to make a quick report. For any real work, using tricks like these is inviting trouble. If selecting a particular row is needed then just have a column with a sequential value and be done with it.

Answer 19

For SQL server, the following will return the first row from giving table.

declare @rowNumber int = 1;
    select TOP(@rowNumber) * from [dbo].[someTable];
EXCEPT
    select TOP(@rowNumber - 1) * from [dbo].[someTable];

You can loop through the values with something like this:

WHILE @constVar > 0
BEGIN
    declare @rowNumber int = @consVar;
       select TOP(@rowNumber) * from [dbo].[someTable];
    EXCEPT
       select TOP(@rowNumber - 1) * from [dbo].[someTable];  

       SET @constVar = @constVar - 1;    
END;

Answer 20

LIMIT n,1 doesn't work in MS SQL Server. I think it's just about the only major database that doesn't support that syntax. To be fair, it isn't part of the SQL standard, although it is so widely supported that it should be. In everything except SQL server LIMIT works great. For SQL server, I haven't been able to find an elegant solution.

Answer 21

In Sybase SQL Anywhere:

SELECT TOP 1 START AT n * from table ORDER BY whatever

Don't forget the ORDER BY or it's meaningless.

Answer 22

T-SQL - Selecting N'th RecordNumber from a Table

select * from
 (select row_number() over (order by Rand() desc) as Rno,* from TableName) T where T.Rno = RecordNumber

Where  RecordNumber --> Record Number to Select
       TableName --> To be Replaced with your Table Name

For e.g. to select 5 th record from a table Employee, your query should be

select * from
 (select row_number() over (order by Rand() desc) as Rno,* from Employee) T where T.Rno = 5

Answer 23

SELECT * FROM emp a
WHERE  n = (SELECT COUNT( _rowid)
              FROM emp b
             WHERE a. _rowid >= b. _rowid);

Answer 24

Nothing fancy, no special functions, in case you use Caché like I do...

SELECT TOP 1 * FROM (
  SELECT TOP n * FROM <table>
  ORDER BY ID Desc
)
ORDER BY ID ASC

Given that you have an ID column or a datestamp column you can trust.

Answer 25

SELECT
    top 1 *
FROM
    table_name
WHERE
    column_name IN (
        SELECT
            top N column_name
        FROM
            TABLE
        ORDER BY
            column_name
    )
ORDER BY
    column_name DESC

I've written this query for finding Nth row. Example with this query would be

SELECT
    top 1 *
FROM
    Employee
WHERE
    emp_id IN (
        SELECT
            top 7 emp_id
        FROM
            Employee
        ORDER BY
            emp_id
    )
ORDER BY
    emp_id DESC

Answer 26

I'm a bit late to the party here but I have done this without the need for windowing or using

WHERE x IN (...)

SELECT TOP 1
--select the value needed from t1
[col2]
FROM
(
   SELECT TOP 2 --the Nth row, alter this to taste
   UE2.[col1],
   UE2.[col2],
   UE2.[date],
   UE2.[time],
   UE2.[UID]
   FROM
   [table1] AS UE2
   WHERE
   UE2.[col1] = ID --this is a subquery 
   AND
   UE2.[col2] IS NOT NULL
   ORDER BY
   UE2.[date] DESC, UE2.[time] DESC --sorting by date and time newest first
) AS t1
ORDER BY t1.[date] ASC, t1.[time] ASC --this reverses the order of the sort in t1

It seems to work fairly fast although to be fair I only have around 500 rows of data

This works in MSSQL

Answer 27

unbelievable that you can find a SQL engine executing this one ...

WITH sentence AS
(SELECT 
    stuff,
    row = ROW_NUMBER() OVER (ORDER BY Id)
FROM 
    SentenceType
    )
SELECT
    sen.stuff
FROM sentence sen
WHERE sen.row = (ABS(CHECKSUM(NEWID())) % 100) + 1

Answer 28

This is how I'd do it within DB2 SQL, I believe the RRN (relative record number) is stored within the table by the O/S;

SELECT * FROM (                        
   SELECT RRN(FOO) AS RRN, FOO.*
   FROM FOO                         
   ORDER BY RRN(FOO)) BAR             
 WHERE BAR.RRN = recordnumber

Answer 29

select * from 
(select * from ordered order by order_id limit 100) x order by 
x.order_id desc limit 1;

First select top 100 rows by ordering in ascending and then select last row by ordering in descending and limit to 1. However this is a very expensive statement as it access the data twice.

Answer 30

It seems to me that, to be efficient, you need to 1) generate a random number between 0 and one less than the number of database records, and 2) be able to select the row at that position. Unfortunately, different databases have different random number generators and different ways to select a row at a position in a result set - usually you specify how many rows to skip and how many rows you want, but it's done differently for different databases. Here is something that works for me in SQLite:

select * 
from Table 
limit abs(random()) % (select count(*) from Words), 1;

It does depend on being able to use a subquery in the limit clause (which in SQLite is LIMIT <recs to skip>,<recs to take>) Selecting the number of records in a table should be particularly efficient, being part of the database's meta data, but that depends on the database's implementation. Also, I don't know if the query will actually build the result set before retrieving the Nth record, but I would hope that it doesn't need to. Note that I'm not specifying an "order by" clause. It might be better to "order by" something like the primary key, which will have an index - getting the Nth record from an index might be faster if the database can't get the Nth record from the database itself without building the result set.