I want to detect if the request came from the localhost:5000
or foo.herokuapp.com
host and what path was requested. How do I get this information about a Flask request?
176
votes
4 Answers
280
votes
You can examine the url through several Request
fields:
Imagine your application is listening on the following application root:
http://www.example.com/myapplication
And a user requests the following URI:
http://www.example.com/myapplication/foo/page.html?x=y
In this case the values of the above mentioned attributes would be the following:
path /foo/page.html full_path /foo/page.html?x=y script_root /myapplication base_url http://www.example.com/myapplication/foo/page.html url http://www.example.com/myapplication/foo/page.html?x=y url_root http://www.example.com/myapplication/
You can easily extract the host part with the appropriate splits.
239
votes
another example:
request:
curl -XGET http://127.0.0.1:5000/alert/dingding/test?x=y
then:
request.method: GET
request.url: http://127.0.0.1:5000/alert/dingding/test?x=y
request.base_url: http://127.0.0.1:5000/alert/dingding/test
request.url_charset: utf-8
request.url_root: http://127.0.0.1:5000/
str(request.url_rule): /alert/dingding/test
request.host_url: http://127.0.0.1:5000/
request.host: 127.0.0.1:5000
request.script_root:
request.path: /alert/dingding/test
request.full_path: /alert/dingding/test?x=y
request.args: ImmutableMultiDict([('x', 'y')])
request.args.get('x'): y
1
votes
If you are using Python, I would suggest by exploring the request object:
dir(request)
Since the object support the method dict:
request.__dict__
It can be printed or saved. I use it to log 404 codes in Flask:
@app.errorhandler(404)
def not_found(e):
with open("./404.csv", "a") as f:
f.write(f'{datetime.datetime.now()},{request.__dict__}\n')
return send_file('static/images/Darknet-404-Page-Concept.png', mimetype='image/png')