reg query a key value based on another key value

Question

What I'm trying to do is have a batch script return the uninstall link for a program. So basically I want something like this:

Select UninstallString from HKLM\SOFTWARE\Wow6432Node\Microsoft\Windows\CurrentVersion\Uninstall where DisplayName='Sublime Text 1.0"

I'm using

reg query HKLM\SOFTWARE\Wow6432Node\Microsoft\Windows\CurrentVersion\Uninstall /S^|find " DisplayName"

to initially get a list of programs, which then get put in a menu, then I select the program to uninstall and it's supposed to go to that program's registry in HKLM\SOFTWARE\Wow6432Node\Microsoft\Windows\CurrentVersion\Uninstall and get it's UninstallString value

I have a list of programs and I want to select the UninstallString from the registry that matches a specific DisplayName? I'm not sure what else you are looking for, I thought I was pretty specific there by give you the exact sql example and asking for the reg query equivalent — Flynn

Endoro Endoro · Accepted Answer · 2013-04-11T23:01:53

Try this:

@echo off&setlocal enabledelayedexpansion
set "regroot=HKLM\SOFTWARE\Wow6432Node\Microsoft\Windows\CurrentVersion\Uninstall"
set "file=%~dpn0.txt"

set /a fcount=0
for /f "delims==" %%i in ('set $ 2^>nul') do set "%%i="
if exist "%file%" (
    for /f "usebackqtokens=1*delims=|" %%i in ("%file%") do (
        set /a fcount+=1
        set "$d%%j=%%j"
        set "$u%%j=%%i"
    )
    goto:menu
)
echo(building "%file%", please wait
for /f "delims=" %%i in ('reg query "%regroot%"') do (
    set "DN="& set "US="
    for /f "tokens=2*" %%j in ('reg query "%regroot%\%%~ni" /v DisplayName 2^>nul^|find /i "DisplayName"') do set "DN=%%~k"
    for /f "tokens=2*" %%j in ('reg query "%regroot%\%%~ni" /v UninstallString 2^>nul^|find /i "UninstallString"') do set "US=%%~k"
    if not "!DN!"=="" if not "!US!"=="" if not defined $d!DN! (
        >>"%file%" echo(!US!^|!DN!
        set /a fcount+=1
        set "$d!DN!=!DN!"
        set "$u!DN!=!US!"
        <nul set/p"=."
    )
)
echo(
:menu
echo(%fcount% programs with uninstall strings found.
:loop
set /a pcount=0
set "program="
set /p "program=type a program name (q=quit): "
if not defined program goto:loop
if "%program%"=="q" goto:eof
echo(
for /f "tokens=2delims==" %%i in ('set $d ^|findstr !program! 2^>nul') do (
    echo(%%i
    echo(!$u%%i!
    echo(
    set /a pcount+=1
)
if %pcount% equ 0 (echo(!program! not found.) else echo(%pcount% program(s^) found.
goto:loop

You can use some of findstr's REGEX capabilities (eg. /i for case insensitive search). Please note: to search for all programs starting with "M" you can use "^$dM" or /b $dM. Searchable strings have always a leading $d.

reg query a key value based on another key value

2 Answers