I have a compile error when using std::function in a templated member function, the following code is a simple example:
#include <functional>
#include <memory>
using std::function;
using std::bind;
using std::shared_ptr;
class Test {
public:
template <typename T>
void setCallback(function<void (T, int)> cb);
};
template <typename T>
void Test::setCallback(function<void (T, int)> cb)
{
// do nothing
}
class TestA {
public:
void testa(int a, int b) { }
};
int main()
{
TestA testA;
Test test;
test.setCallback(bind(&TestA::testa, &testA, std::placeholders::_1, std::placeholders::_2));
return 0;
}
And come with the following compile error:
testtemplate.cpp: In function ‘int main()’:
testtemplate.cpp:29:92: error: no matching function for call to ‘Test::setCallback(std::_Bind_helper)(int, int), TestA, const std::_Placeholder<1>&, const std::_Placeholder<2>&>::type)’
testtemplate.cpp:29:92: note: candidate is: testtemplate.cpp:10:7: note: template void Test::setCallback(std::function)
testtemplate.cpp:10:7: note: template argument deduction/substitution failed:
testtemplate.cpp:29:92: note: ‘std::_Bind(TestA*, std::_Placeholder<1>, std::_Placeholder<2>)>’ is not derived from ‘std::function’
I'm using C++11 and g++ 4.7
test.setCallback<int>(bind...)
. The result ofbind
is not anstd::function
, so there's no argument deduction. – Kerrek SBT
to. – Xeostd::function
is a parameter, you have to spell out the type fully unless you pass astd::function
. – Matthieu M.std::bind
– sweenish