The following generic type contains the type parameter A two times:
class Something<B<A>, A>
I wonder if it would be possible to write only class Something<B<A>> because A is already given through B<A>.
I think it is not possible, but maybe I've overlooked something.
Awithin the classSomething, you'll have to leave it as two type parameters as the type parameter toBwill be unavailable toSomething- Peter Ritchie