I was trying to delete lines in a text which contain any word in a list. For example:
File 1:
xxx yyy, zzz,
aaa bbb, sss,
ccc fff, zzz,
rrr www, qasd,
File 2:
xxx
zzz
rrr
The target is to delete the lines in file1 which contain any word in file2. So the output should be:
aaa bbb, sss,
I know how to use sed with single word, like sed '/zzz/d' to delete lines containing zzz. But how it works in multiple words, or words in a file?
You can do this easily with grep:
$ grep -Fwvf file2 file1
aaa bbb, sss,
Options:
-f FILE, --file=FILE
Obtain patterns from FILE, one per line. The empty file contains zero patterns, and therefore matches nothing. (-f is specified by POSIX.)
-v, --invert-match
Invert the sense of matching, to select non-matching lines. (-v is specified by POSIX.)
-w, --word-regexp
Select only those lines containing matches that form whole words. The test is that the matching substring must either be at the beginning of the line, or preceded by a non-word constituent character. Similarly, it must be either at the end of the line or followed by a non-word constituent character. Word-constituent characters are letters, digits, and the underscore.
-F, --fixed-strings
Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched. (-F is specified by POSIX.)
To store the changes back to file1:
$ grep -Fwvf file2 file1 > tmp && mv tmp file1
