Access chef resources inside ruby block

Question

I've been trying to find the answer to this in the chef docs and through Google, but I've not been able to come up with anything. I'm not a ruby guy (yet), so the answer to this might stem from my approaching the problem with "just enough ruby for Chef". Here's what I want to do: in my deploy resource, in the before_migrate attribute, I want to execute a resource in my current recipe. What I am doing currently is to just stuff the resource into the block itself, but I know there must be a better way to do it.

before_migrate do

    template "#{app_root}/#{applet_name}/local_settings.py" do
        source "local_settings.py.erb"
        owner app_config['user']
        group app_config['group']
        variables(
            :database_name => app_config['postgresql']['database_name'],
            :user => app_config['postgresql']['user'],
            :password => app_config['postgresql']['password']
        )   
        action :create
    end 
end

What I'm aiming for is something like

before_migrate do
    "template #{app_root}/#{applet_name}/local_settings.py".execute
end

So I can re-use that template code. Thanks!

Giannis Nohj Giannis Nohj · Accepted Answer · 2013-02-19T14:50:00

You could specify the resource outside of the "deploy" resource with an action of nothing and then, in the *before_migrate* do something like:

    before_migrate do

        ruby_block "notify_template" do
            block do
              true
            end
            action :create
            notifies :create, "template[#{app_root}/#{applet_name}/local_settings.py]", :immediately
        end

     end

That way, you can notify it when you need it.

Access chef resources inside ruby block

2 Answers