1
votes

Good day everybody! I'm currently trying to figure something out in excel before implementing in it VBScript. I have to mathematically transpose a few cells (10*10 or 5r*10c) in a matrice:

-------------------------------
| .. | .. | .. | .. | .. | .. |
| 21 | 22 | 23 | 24 | 25 | .. |
| 11 | 12 | 13 | 14 | 15 | .. |
|  1 |  2 |  3 |  4 |  5 | .. |
-------------------------------

Must become

-------------------------------
| .. | .. | .. | .. | .. | .. |
|  3 | 13 | 23 | 33 | 43 | .. |
|  2 | 12 | 22 | 32 | 42 | .. |
|  1 | 11 | 21 | 31 | 41 | .. |
-------------------------------

Now I'm not a mathematician (I'm more ore less a programmer at the moment), but I came up with: F(y)=((MOD(x,10)-1)*10)+(1+((x-MOD(x,10))/10)) (x is the value in the pre-block a the top, y is the value in the pre-block below.) Now this works fine up to a certain point (e.g. 10).

In VBScript, I wrote the below at first:

Function GetPosInSrcRack(Pos)
    Dim PlateDef(9), x, y, i, tmp

    ' Plate Definition
    ReDim tmp(UBound(PlateDef))
    For x = 0 To UBound(PlateDef)
        PlateDef(x) = tmp
    Next

    i = 1
    For x = 0 To UBound(PlateDef)
        For y = 0 To UBound(PlateDef(x))
            PlateDef(x)(y) = i
            i = (i + 1)
        Next
    Next

    'Dim msg ' Check definition
    'For x = 0 To (UBound(PlateDef))
    '    msg = Join(PlateDef(x), ", ") & vbCrLf & msg
    'Next

    ' Get the Position
    y = (pos Mod 10)
    x = ((pos - y) / 10)

    GetPosInSrcRack = PlateDef(y)(x)
End Function

Which, of course, works but is crappy.

Using the above formula I would write:

Function GetPosInSrcRack(Pos)
    Pos = (((Pos MOD 10)-1)*10)+(1+((Pos - (Pos MOD 10))/10))
End Function

But like I said, this still is incorrect (10 gives -8) Can somebody help me?

2

2 Answers

1
votes
y=(MOD(x-1,10))*10+INT((x-1)/10)+1

(By the way, what you are doing is not matrix transposition, but this does do what you do, only better.)

2
votes

Just use Paste Special > Transpose option.