Following this post: multicore and data.table in R, I was wondering if there was a way to use all cores when using data.table, typically doing calculations by groups could be parallelized. It seems that plyr allows such operations by design.
42
votes
3 Answers
54
votes
First thing to check is that data.table FAQ 3.1 point 2 has sunk in :
One memory allocation is made for the largest group only, then that memory is reused for the other groups. There is very little garbage to collect.
That's one reason data.table grouping is quick. But this approach doesn't lend itself to parallelization. Parallelizing means copying the data to the other threads, instead, costing time. But, my understanding is that data.table grouping is usually faster than plyr with .parallel on anyway. It depends on the computation time of the task for each group, and if that compute time can be easily reduced or not. Moving the data around often dominates (when benchmarking 1 or 3 runs of large data tasks).
More often, so far, it's actually some gotcha that's biting in the j expression of [.data.table. For example, recently we saw poor performance from data.table grouping but the culprit turned out to be min(POSIXct) (Aggregating in R over 80K unique ID's). Avoiding that gotcha yielded over 50 times speedup.
So the mantra is: Rprof, Rprof, Rprof.
Further, point 1 from the same FAQ might be significant :
Only that column is grouped, the other 19 are ignored because data.table inspects the j expression and realises it doesn’t use the other columns.
So, data.table really doesn't follow the split-apply-combine paradigm at all. It works differently. split-apply-combine lends itself to parallelization but it really doesn't scale to large data.
Also see footnote 3 in the data.table intro vignette :
We wonder how many people are deploying parallel techniques to code that is vector scanning
That's trying to say "sure, parallel is significantly faster, but how long should it really take with an efficient algorithm?".
BUT if you've profiled (using Rprof), and the task per group really is compute intensive, then the 3 posts on datatable-help including the word "multicore" might help:
multicore posts on datatable-help
Of course there are many tasks where parallelization would be nice in data.table, and there is a way to do it. But it hasn't been done yet, since usually other factors bite, so it's been low priority. If you can post reproducible dummy data with benchmarks and Rprof results, that would help increase the priority.
9
votes
I've done some tests per @matt dowle's prior mantra of Rprof, Rprof, Rprof.
What I find is that the decision to parallelize is context dependent; but is likely significant. Depending on the test operations (eg foo below, which can be customized) and the number of cores utilized (I try both 8 and 24), I get different results.
Below results:
- using 8 cores, I see a 21% improvement in this example for parallelization
- using 24 cores, I see 14% improvement.
I also look at some real-world (non shareable) data / operations which shows a larger (33% or 25%, two different tests) improvement paralellizing with 24 cores. Edit May 2018 A new set of real-world example cases are showing closer to 85% improvements from parallel operations with 1000 groups.
R> sessionInfo() # 24 core machine:
R version 3.3.2 (2016-10-31)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: CentOS Linux 7 (Core)
attached base packages:
[1] parallel stats graphics grDevices utils datasets methods
[8] base
other attached packages:
[1] microbenchmark_1.4-2.1 stringi_1.1.2 data.table_1.10.4
R> sessionInfo() # 8 core machine:
R version 3.3.2 (2016-10-31)
Platform: x86_64-apple-darwin13.4.0 (64-bit)
Running under: macOS Sierra 10.12.4
attached base packages:
[1] parallel stats graphics grDevices utils datasets methods base
other attached packages:
[1] microbenchmark_1.4-2.1 stringi_1.1.5 data.table_1.10.4
Example below:
library(data.table)
library(stringi)
library(microbenchmark)
set.seed(7623452L)
my_grps <- stringi::stri_rand_strings(n= 5000, length= 10)
my_mat <- matrix(rnorm(1e5), ncol= 20)
dt <- data.table(grps= rep(my_grps, each= 20), my_mat)
foo <- function(dt) {
dt2 <- dt ## needed for .SD lock
nr <- nrow(dt2)
idx <- sample.int(nr, 1, replace=FALSE)
dt2[idx,][, `:=` (
new_var1= V1 / V2,
new_var2= V4 * V3 / V10,
new_var3= sum(V12),
new_var4= ifelse(V10 > 0, V11 / V13, 1),
new_var5= ifelse(V9 < 0, V8 / V18, 1)
)]
return(dt2[idx,])
}
split_df <- function(d, var) {
base::split(d, get(var, as.environment(d)))
}
foo2 <- function(dt) {
dt2 <- split_df(dt, "grps")
require(parallel)
cl <- parallel::makeCluster(min(nrow(dt), parallel::detectCores()))
clusterExport(cl, varlist= "foo")
clusterExport(cl, varlist= "dt2", envir = environment())
clusterEvalQ(cl, library("data.table"))
dt2 <- parallel::parLapply(cl, X= dt2, fun= foo)
parallel::stopCluster(cl)
return(rbindlist(dt2))
}
print(parallel::detectCores()) # 8
microbenchmark(
serial= dt[,foo(.SD), by= "grps"],
parallel= foo2(dt),
times= 10L
)
Unit: seconds
expr min lq mean median uq max neval cld
serial 6.962188 7.312666 8.433159 8.758493 9.287294 9.605387 10 b
parallel 6.563674 6.648749 6.976669 6.937556 7.102689 7.654257 10 a
print(parallel::detectCores()) # 24
Unit: seconds
expr min lq mean median uq max neval cld
serial 9.014247 9.804112 12.17843 13.17508 13.56914 14.13133 10 a
parallel 10.732106 10.957608 11.17652 11.06654 11.30386 12.28353 10 a
Profiling:
We can use this answer to provide a more direct response to @matt dowle's original comment to profiling.
As a result, we do see that the majority of compute time is handled by base and not data.table. data.table operations themselves are, as expected, exceptionally fast. While some might argue that this is evidence that there is no need for parallelism within data.table, I posit that this workflow/operation-set is not atypical. That is, it is my strong suspicion that the majority of large data.table aggregation involve a substantial amount of non-data.table code; and that this is correlated with interactive use vs development / production use. I therefore conclude that parallelism would be valuable within data.table for large aggregations.
library(profr)
prof_list <- replicate(100, profr::profr(dt[,foo(.SD), by= "grps"], interval = 0.002),
simplify = FALSE)
pkg_timing <- fun_timing <- vector("list", length= 100)
for (i in 1:100) {
fun_timing[[i]] <- tapply(prof_list[[i]]$time, paste(prof_list[[i]]$source, prof_list[[i]]$f, sep= "::"), sum)
pkg_timing[[i]] <- tapply(prof_list[[i]]$time, prof_list[[i]]$source, sum)
}
sort(sapply(fun_timing, sum)) # no large outliers
fun_timing2 <- rbindlist(lapply(fun_timing, function(x) {
ret <- data.table(fun= names(x), time= x)
ret[, pct_time := time / sum(time)]
return(ret)
}))
pkg_timing2 <- rbindlist(lapply(pkg_timing, function(x) {
ret <- data.table(pkg= names(x), time= x)
ret[, pct_time := time / sum(time)]
return(ret)
}))
fun_timing2[, .(total_time= sum(time),
avg_time= mean(time),
avg_pct= round(mean(pct_time), 4)), by= "fun"][
order(avg_time, decreasing = TRUE),][1:10,]
pkg_timing2[, .(total_time= sum(time),
avg_time= mean(time),
avg_pct= round(mean(pct_time), 4)), by= "pkg"][
order(avg_time, decreasing = TRUE),]
Results:
fun total_time avg_time avg_pct
1: base::[ 670.362 6.70362 0.2694
2: NA::[.data.table 667.350 6.67350 0.2682
3: .GlobalEnv::foo 335.784 3.35784 0.1349
4: base::[[ 163.044 1.63044 0.0655
5: base::[[.data.frame 133.790 1.33790 0.0537
6: base::%in% 120.512 1.20512 0.0484
7: base::sys.call 86.846 0.86846 0.0348
8: NA::replace_dot_alias 27.824 0.27824 0.0112
9: base::which 23.536 0.23536 0.0095
10: base::sapply 22.080 0.22080 0.0089
pkg total_time avg_time avg_pct
1: base 1397.770 13.97770 0.7938
2: .GlobalEnv 335.784 3.35784 0.1908
3: data.table 27.262 0.27262 0.0155
crossposted in github/data.table
1
votes
Yes (though, it may not be worth it, as well pointed out by @Alex W).
The following provides a simple pattern to do so. For simplicity of exposition I use an example in which it is not worth it (using the mean function), but it shows of the pattern.
Example:
Suppose you want to compute the mean Petal.Length by Species in the iris data-set.
You could do it pretty directly using data.table as:
as.data.table(iris)[by=Species,,.(MPL=mean(Petal.Length))]
Species MPL
1: setosa 1.462
2: versicolor 4.260
3: virginica 5.552
But, if mean was instead a sufficiently long-running and expensive computation (perhaps as determined by profiling though sometimes it is just "obvious"), you may like to use parallel::mclapply. Since minimizing the communication with all the sub-processes mclapply spawns can greatly reduce overall computation, instead of passing selections from the data.table to each sub-process, you want to pass just the indices of the selection. Further, by sorting the data.table first, you can pass just the range (max and min) of these indices. Like this:
> o.dt<-as.data.table(iris)[order(Species)] # note: iris happens already to be ordered
> i.dt<-o.dt[,by=Species,.(irange=.(range(.I)))]
> i.dt
Species irange
1: setosa 1,50
2: versicolor 51,100
3: virginica 101,150
> result<-mclapply(seq(nrow(i.dt)),function(r) o.dt[do.call(seq,as.list(i.dt[r,irange][[1]])),.(MPL=mean(Petal.Length))])
> result
[[1]]
MPL
1: 1.462
[[2]]
MPL
1: 4.26
[[3]]
MPL
1: 5.552
> result.dt<-cbind(i.dt,rbindlist(result))[,-2]
> result.dt
Species MPL
1: setosa 1.462
2: versicolor 4.260
3: virginica 5.552
Reviewing the pattern:
- Order the input.
- Compute the index range for each group.
- Define an anonymous
functionto extract the rows comprising the group members, and perform the required computation (in this case, mean). - Apply the function to each group using mclapply on the row indices of the index ranges.
- Use
rbindlistto get the results as a data.table,cbindit to the input, and drop it index columns (unless you need to keep them around for some other reason).
Notes:
- The final
rbindlistis generally expensive and may be skipped depending upon your application).
ToDo:
- convince data.table team that this pattern is sufficiently general and useful enough that additional data.table indexing options should invoke it. Imagine, passing mc=TRUE would invoke this pattern, and support additional parallel options in ...
iris.dt[by=Species,,.(MPL=mean(Petal.Length)), mc=TRUE, mc.preschedule=FALSE, mc.set.seed=TRUE,...]
