I'm a beginner in lisp and I need somebody to explain to me how the prog form works, step by step. What is the initial value of l1 ? Nil ?
The problem outputs T if the list has an even number of elements on the first level, nil if not.
(defun nr_par (l)
(prog ((l1 l))
ciclu
(cond
((null l1) (return T))
((null (cdr l1)) (return NIL))
((null (cddr l1)) (return T))
(T (setf l1 (cddr l1))
(go ciclu)))))
On console:
(nr_par '(1 2 3 4 5 6 7 8))
T