What is the difference between Math.Floor()
and Math.Truncate()
in .NET?
13 Answers
Math.Floor
rounds down, Math.Ceiling
rounds up, and Math.Truncate
rounds towards zero. Thus, Math.Truncate
is like Math.Floor
for positive numbers, and like Math.Ceiling
for negative numbers. Here's the reference.
For completeness, Math.Round
rounds to the nearest integer. If the number is exactly midway between two integers, then it rounds towards the even one. Reference.
See also: Pax Diablo's answer. Highly recommended!
Follow these links for the MSDN descriptions of:
Math.Floor
, which rounds down towards negative infinity.Math.Ceiling
, which rounds up towards positive infinity.Math.Truncate
, which rounds up or down towards zero.Math.Round
, which rounds to the nearest integer or specified number of decimal places. You can specify the behavior if it's exactly equidistant between two possibilities, such as rounding so that the final digit is even ("Round(2.5,MidpointRounding.ToEven)
" becoming 2) or so that it's further away from zero ("Round(2.5,MidpointRounding.AwayFromZero)
" becoming 3).
The following diagram and table may help:
-3 -2 -1 0 1 2 3
+--|------+---------+----|----+--|------+----|----+-------|-+
a b c d e
a=-2.7 b=-0.5 c=0.3 d=1.5 e=2.8
====== ====== ===== ===== =====
Floor -3 -1 0 1 2
Ceiling -2 0 1 2 3
Truncate -2 0 0 1 2
Round (ToEven) -3 0 0 2 3
Round (AwayFromZero) -3 -1 0 2 3
Note that Round
is a lot more powerful than it seems, simply because it can round to a specific number of decimal places. All the others round to zero decimals always. For example:
n = 3.145;
a = System.Math.Round (n, 2, MidpointRounding.ToEven); // 3.14
b = System.Math.Round (n, 2, MidpointRounding.AwayFromZero); // 3.15
With the other functions, you have to use multiply/divide trickery to achieve the same effect:
c = System.Math.Truncate (n * 100) / 100; // 3.14
d = System.Math.Ceiling (n * 100) / 100; // 3.15
Math.floor
sliiiide to the left...Math.ceil
sliiiide to the right...Math.truncate
criiiiss crooooss (floor/ceil always towards 0)Math.round
cha cha, real smooth... (go to closest side)
Let's go to work! (⌐□_□)
To the left... Math.floor
Take it back now y'all... --
Two hops this time... -=2
Everybody clap your hands ✋✋
How low can you go? Can you go down low? All the way to the floor
?
if (this == "wrong")
return "i don't wanna be right";
Math.truncate(x)
is also the same as int(x)
.
by removing a positive or negative fraction, you're always heading towards 0.
Some examples:
Round(1.5) = 2
Round(2.5) = 2
Round(1.5, MidpointRounding.AwayFromZero) = 2
Round(2.5, MidpointRounding.AwayFromZero) = 3
Round(1.55, 1) = 1.6
Round(1.65, 1) = 1.6
Round(1.55, 1, MidpointRounding.AwayFromZero) = 1.6
Round(1.65, 1, MidpointRounding.AwayFromZero) = 1.7
Truncate(2.10) = 2
Truncate(2.00) = 2
Truncate(1.90) = 1
Truncate(1.80) = 1
They are functionally equivalent with positive numbers. The difference is in how they handle negative numbers.
For example:
Math.Floor(2.5) = 2
Math.Truncate(2.5) = 2
Math.Floor(-2.5) = -3
Math.Truncate(-2.5) = -2
MSDN links: - Math.Floor Method - Math.Truncate Method
P.S. Beware of Math.Round it may not be what you expect.
To get the "standard" rounding result use:
float myFloat = 4.5;
Console.WriteLine( Math.Round(myFloat) ); // writes 4
Console.WriteLine( Math.Round(myFloat, 0, MidpointRounding.AwayFromZero) ) //writes 5
Console.WriteLine( myFloat.ToString("F0") ); // writes 5
Try this, Examples:
Math.Floor() vs Math.Truncate()
Math.Floor(2.56) = 2
Math.Floor(3.22) = 3
Math.Floor(-2.56) = -3
Math.Floor(-3.26) = -4
Math.Truncate(2.56) = 2
Math.Truncate(2.00) = 2
Math.Truncate(1.20) = 1
Math.Truncate(-3.26) = -3
Math.Truncate(-3.96) = -3
Also Math.Round()
Math.Round(1.6) = 2
Math.Round(-8.56) = -9
Math.Round(8.16) = 8
Math.Round(8.50) = 8
Math.Round(8.51) = 9
math.floor()
Returns the largest integer less than or equal to the specified number. MSDN system.math.floor
math.truncate()
Calculates the integral part of a number. MSDN system.math.truncate
Math.Floor()
rounds
"toward negative infinity" in compliance to IEEE Standard 754 section 4.
Math.Truncate()
rounds " to the nearest integer towards zero."
Math.Floor() :
It gives the largest integer less than or equal to the given number.
Math.Floor(3.45) =3
Math.Floor(-3.45) =-4
Math.Truncate():
It removes the decimal places of the number and replace with zero
Math.Truncate(3.45)=3
Math.Truncate(-3.45)=-3
Also from above examples we can see that floor and truncate are same for positive numbers.