error in opening website from ipv6 address

Question

I have installed apache2 in my ubunntu 12.10 system with inet addr 172.16.17.235 and inet6 addr fe80::a05b:25ff:fef0:68a4/64 in LAN.

Now when i want to open default website (index.html) located in /var/www/ , i simply write
http://localhost or
http://127.0.0.1 or
http://172.16.17.235 in my web browser(firefox 17.0) and it opens that index.html page
but when i want to access this index.html with the help of ipv6 addressing as below :
http://[::1] or
http://[fe80::a05b:25ff:fef0:68a4]

following error is shown by browser :
Unable to connect Firefox
can't establish a connection to the server at [::1] or
Firefox can't establish a connection to the server at [fe80::a05b:25ff:fef0:68a4].

Can any one tell me what configuration am i missing in my system or what i am doing wrong.

BTW when i ping to my localhost as :
ping6 ::1 or ping6 -I eth0 fe80::a05b:25ff:fef0:68a4
ping reply is coming fine as :
64 bytes from ::1: icmp_seq=1 ttl=64 time=0.032 ms
or
64 bytes from fe80::a05b:25ff:fef0:68a4: icmp_seq=1 ttl=64 time=0.048 ms

glglgl glglgl · Accepted Answer · 2012-11-22T11:38:30

If you want to use an IPv6 address from the fe80:: range, you must specify over which network adapter it should go. (Technically, you must provide the Zone ID which correlates with the network adapter used).

On ping, you do that with -l eth0. In Firefox, you can do that with http://[fe80::a05b:25ff:fef0:68a4%x] where x is a positive number you must find out.

EDIT: If you absolutely don't find out what is going on, you could try this:

python -c 'import sys,socket; print socket.getaddrinfo(sys.argv[1], (sys.argv[2:]+[0])[0], 0, socket.SOCK_STREAM)' fe80::a05b:25ff:fef0:68a4%eth0

and have a look to the result. On my system, it looks like

[(10, 1, 6, '', ('fe80::a05b:25ff:fef0:68a4%eth0', 0, 0, 3))]

where the last number, the 3, is the real Zone ID.

If this gives you a result, your name resolution works fine, if not, it is broken.

The next step could be to try to create a HTTP connection:

python -c 'import sys,socket; c=socket.create_connection((sys.argv[1], 80)); c.send("GET / HTTP/1.0\n\n"); print c.recv(100000).split("\r\n\r\n",1)[0]' fe80::a05b:25ff:fef0:68a4%eth0

If that works, the problem is your browser, if not, you cannot reach the server due to whatever reason. (Does your web server daemon bind to IPv6?)

error in opening website from ipv6 address

1 Answers