scheme-procedure that takes list as argument

Question

I have to write a Scheme procedure named 'proc3' which takes 2 numbers as arguments (x,y) and returns a procedure which takes a list as an argument and returns a new list which is the same as the input list but with x added as the first element and y added as the second element.

I have so far (define proc3 (lambda ( x y) (lambda (list a b c) (list x y c) ) ) )

The interpreter compiles it fine, but when I give arguments i.e proc3( 1 2), it says: cannot reference an identifier before definition. What does that mean?

Óscar López Óscar López · Accepted Answer · 2012-11-12T04:16:20

The code in the question won't work. Use this as a template for your solution, noticing that a list is just another parameter (I called it lst) e.g., you don't have to write list and enumerate its elements as you did:

(define proc3
  (lambda (x y)
    (lambda (lst)
      <add x y at head of lst>)))

I'll let you figure out the details of how to add x and y at the beginning of lst. For testing it, try something like this:

((proc3 1 2) '(3 4 5))
=> '(1 2 3 4 5)

scheme-procedure that takes list as argument

1 Answers