Load all data files in a directory in Octave

3
votes

I need to load all data in a directory into octave (no matter what their filenames are), so that the data from separate files are loaded into separate matrices. How can I do that?

I've tried to use dir and glob and then use a for loop but I don't know how to get matrices from cells.

2
matrixdirectoryoctave
stackoverflow.com/a/57211827/2244676 – Oleksandr

2 Answers

7
votes

I'm not 100% sure of your question. When you mention getting matrices from cells I'm guessing your problem is extracting the filename from the output of readir and glob. If that's so, you can get the names with filenames(1) (if you use {} to index a cell array you get another cell array).

filelist = readdir (pwd)
for ii = 1:numel(filelist)
  ## skip special files . and ..
  if (regexp (filelist{ii}, "^\\.\\.?$"))
    continue;
  endif
  ## load your file
  load filelist{ii}
  ## do your maths
endfor

You can use a struct on the load line if the filenames are good data.(filelist{ii}) = load filelist{ii}.

0
votes

The answer by carandraug is great, I only want to specify that in some Octave versions, the load line may need to be written as:

load (filelist{ii})