95
votes
var fd = new FormData();
fd.append("fileToUpload", document.getElementById('fileToUpload').files[0]);
var xhr = new XMLHttpRequest();
xhr.open("POST", "uph.php");
xhr.send(fd);

uph.php:

var_dump($_FILES['fileToUpload']);

This works, but obviously for the files[0] only. How to get this working for chosen file?

I tried removing the [0], but it didn't work.

14

14 Answers

107
votes

You have to get the files length to append in JS and then send it via AJAX request as below

//JavaScript 
var ins = document.getElementById('fileToUpload').files.length;
for (var x = 0; x < ins; x++) {
    fd.append("fileToUpload[]", document.getElementById('fileToUpload').files[x]);
}

//PHP
$count = count($_FILES['fileToUpload']['name']);
for ($i = 0; $i < $count; $i++) {
    echo 'Name: '.$_FILES['fileToUpload']['name'][$i].'<br/>';
}
81
votes

The way to go with javascript:

var data = new FormData();

$.each($("input[type='file']")[0].files, function(i, file) {
    data.append('file', file);
});

$.ajax({
    type: 'POST',
    url: '/your/url',
    cache: false,
    contentType: false,
    processData: false,
    data : data,
    success: function(result){
        console.log(result);
    },
    error: function(err){
        console.log(err);
    }
})

If you call data.append('file', file) multiple times your request will contain an array of your files.

From MDN web docs:

"The append() method of the FormData interface appends a new value onto an existing key inside a FormData object, or adds the key if it does not already exist. The difference between FormData.set and append() is that if the specified key already exists, FormData.set will overwrite all existing values with the new one, whereas append() will append the new value onto the end of the existing set of values."

Myself using node.js and multipart handler middleware multer get the data as follows:

router.post('/trip/save', upload.array('file', 10), function(req, res){
    // Your array of files is in req.files
}
25
votes

You just have to use fileToUpload[] instead of fileToUpload :

fd.append("fileToUpload[]", document.getElementById('fileToUpload').files[0]);

And it will return an array with multiple names, sizes, etc...

17
votes

This worked for me:

let formData = new FormData()
formData.append('files', file1)
formData.append('files', file2)
9
votes

This one worked for me

//Javascript part
//file_input is a file input id
var formData = new FormData();
var filesLength=document.getElementById('file_input').files.length;
for(var i=0;i<filesLength;i++){
	formData.append("file[]", document.getElementById('file_input').files[i]);
}
$.ajax({
   url: 'upload.php',
   type: 'POST',
   data: formData,
   contentType: false,
   cache: false,
   processData: false,
   success: function (html) {
   
  }
});

<?php
//PHP part
$file_names = $_FILES["file"]["name"];
for ($i = 0; $i < count($file_names); $i++) {
   $file_name=$file_names[$i];
   $extension = end(explode(".", $file_name));
   $original_file_name = pathinfo($file_name, PATHINFO_FILENAME);
   $file_url = $original_file_name . "-" . date("YmdHis") . "." . $extension;
 move_uploaded_file($_FILES["file"]["tmp_name"][$i], $absolute_destination . $file_url);
}
6
votes

Adding [] when appending to fd works, but if you prefer to have your data grouped by file then I'd suggest doing it this way:

var files= document.getElementById('inpFile').files
var fd = new FormData()

for (let i = 0; i < files.length; i++) {
  fd.append(i, files[i])
}

Now your data will be sent grouped by file instead of grouped by attribute.

4
votes

This worked fine !

var fd = new FormData();

$('input[type="file"]').on('change', function (e) {
    [].forEach.call(this.files, function (file) {
        fd.append('filename[]', file);
    });
});

$.ajax({
    url: '/url/to/post/on',
    method: 'post',
    data: fd,
    contentType: false,
    processData: false,
    success: function (response) {
        console.log(response)
    },
    error: function (err) {
        console.log(err);
    }
});
2
votes

This worked for me

var ins = $('.file').map(function () {
    return this.files;
}).get();

for (var x = 0; x < ins; x++) {
    formData.append("file", ins[x][0]);
}
1
votes

I found this work for me!

var fd = new FormData();
$.each($('.modal-banner [type=file]'), function(index, file) {
  fd.append('item[]', $('input[type=file]')[index].files[0]);
});

$.ajax({
  type: 'POST',
  url: 'your/path/', 
  data: fd,
  dataType: 'json',
  contentType: false,
  processData: false,
  cache: false,
  success: function (response) {
    console.log(response);
  },
  error: function(err){
    console.log(err);
  }
}).done(function() {
  // do something....
});
return false;
1
votes

To upload multiple files with angular form data, make sure you have this in your component.html

Upload Documents

                <div class="row">


                  <div class="col-md-4">
                     &nbsp; <small class="text-center">  Driver  Photo</small>
                    <div class="form-group">
                      <input  (change)="onFileSelected($event, 'profilepic')"  type="file" class="form-control" >
                    </div>
                  </div>

                  <div class="col-md-4">
                     &nbsp; <small> Driver ID</small>
                    <div class="form-group">
                      <input  (change)="onFileSelected($event, 'id')"  type="file" class="form-control" >
                    </div>
                  </div>

                  <div class="col-md-4">
                    &nbsp; <small>Driving Permit</small>
                    <div class="form-group">
                      <input type="file"  (change)="onFileSelected($event, 'drivingpermit')" class="form-control"  />
                    </div>
                  </div>
                </div>



                <div class="row">
                    <div class="col-md-6">
                       &nbsp; <small>Car Registration</small>
                      <div class="form-group">
                        <div class="input-group mb-4">
                            <input class="form-control" 
                (change)="onFileSelected($event, 'carregistration')" type="file"> <br>
                        </div>
                      </div>
                    </div>

                    <div class="col-md-6">
                        <small id="li"> Car Insurance</small>
                      <div class="form-group">
                        <div class="input-group mb-4">
                          <input class="form-control" (change)="onFileSelected($event, 

                         'insurancedocs')"   type="file">
                        </div>
                      </div>
                    </div>

                  </div>


                <div style="align-items:c" class="modal-footer">
                    <button type="button" class="btn btn-secondary" data- 
                  dismiss="modal">Close</button>
                    <button class="btn btn-primary"  (click)="uploadFiles()">Upload 
                  Files</button>
                  </div>
              </form>

In your componenet.ts file declare array selected files like this

selectedFiles = [];

// array of selected files

onFileSelected(event, type) {
    this.selectedFiles.push({ type, file: event.target.files[0] });
  }

//in the upload files method, append your form data like this

uploadFiles() {
    const formData = new FormData(); 

    this.selectedFiles.forEach(file => {
      formData.append(file.type, file.file, file.file.name); 
    });
    formData.append("driverid", this.driverid);

    this.driverService.uploadDriverDetails(formData).subscribe(
      res => {
        console.log(res); 

      },
      error => console.log(error.message)
    );
  }

NOTE: I hope this solution works for you friends

1
votes

I worked that such as:

var images = document.getElementById('fileupload').files;
var formData = new FormData();
for(i=0; i<images.length; i++) {
     formData.append('files', images[i]);
}
0
votes

Create a FormData object

const formData: any = new FormData();

And append to the same keyName

photos.forEach((_photoInfo: { localUri: string, file: File }) => {
    formData.append("file", _photoInfo.file);
});

and send it to server

// angular code
this.http.post(url, formData)

this will automatically create an array of object under file

if you are using nodejs

const files :File[] = req.files ? req.files.file : null;
0
votes

Here is the Vanilla JavaScript solution for this issue -

First, we'll use Array.prototype.forEach() method, as

document.querySelectorAll('input[type=file]') returns an array like object.

Then we'll use the Function.prototype.call() method to assign each element in the array-like object to the this value in the .forEach method.

HTML

<form id="myForm">

    <input type="file" name="myFile" id="myFile_1">
    <input type="file" name="myFile" id="myFile_2">
    <input type="file" name="myFile" id="myFile_3">

    <button type="button" onclick="saveData()">Save</button>

</form>

JavaScript

 function saveData(){
     var data = new FormData(document.getElementById("myForm"));
     var inputs = document.querySelectorAll('input[type=file]');

     Array.prototype.forEach.call(inputs[0].files, function(index){
        data.append('files', index);
     });
     console.log(data.getAll("myFile"));
}

You can view the working example of the same HERE

0
votes

If you are instantiating the FormData object already passing the form as a constructor parameter, the input file's name attribute must contain the square brackets.

HTML:

<form id="myForm" method="POST" action="url" enctype="multipart/form-data">
<input class="form-control form-control-lg" type="file" name="photos[]" multiple />

JS:

var formData = new FormData(document.getElementById('myForm'));
console.log(formData.getAll('photos[]'));

That worked for me!