Say I have 3x3 cells, each cell containing a matrix of 9x9, how would I go about using cellfun to sum each row of the entire cell array?
I keep obtaining the error ''bad cell reference'' when I try to use the : in the curly brackets.
I'd rather not convert it to a matrix then back to cells again.
Many thanks for your wisdom guys!
Here is the solution for summing row of each matrix with a cell , if you read the documentation of cellfun carefully, I think you should be able to get it.
clc;
clear all;
a=cell(3,3);
for i=1:3
for j=1:3
a{i,j}=randi(10,[9 9]);
end
end
row_sum_cell=cellfun(@(a) sum(a,2),a,'UniformOutput',false);
The following solution sums the entire row across the cell array:
clc;
clear all;
a=cell(3,3);
for i=1:3
for j=1:3
a{i,j}=randi(10,[9 9]); %generating the cell array
end
end
[r,c]=size(a); %getting the size of the array to concatenate it at runtime
horzCat_A=cell(r,1);
for i=1:r
for j=1:c
horzCat_A{i,1}=[horzCat_A{i,1} a{i,j}]; %concatenating
end
end
%after getting a concatenated matrix, apply a cellfun same as in previous example.
cell_row_sum=cellfun(@(horzCat_A) sum(horzCat_A,2),horzCat_A,'UniformOutput',false);
If you mean sum each row in each cell entry maybe you can do something like this:
% random input
A = cell(3,3);
for i=1:9
A{i} = randi(9,3,3);
end;
B = cellfun(@(x) sum(x, 2), A, 'UniformOutput', false);
Update: To sum all rows across the cell array, as if it was a matrix, without converting to a matrix modify the above as:
B = num2cell(zeros(3, 1)); % initialize
for i=1:3
B = cellfun(@plus, B, A(:,i), 'UniformOutput', false); % add column-wise
end
B = cellfun(@(x) sum(x, 2), B, 'UniformOutput', false); % add within each remaning cell
This will give a 3x1 cell of 3x1 arrays with the sums across rows.
