I have a dell laptop latitude 5420.
The built-in monitor has a width of 12.20 inches and a height of 6.69 6,86 inches.
OS is Windows7. The screen resolution is set to 1600 by 900 (prefered resolution).
Additionally Windows7 is configured with a "Set custom text size (DPI)" of 100% (9 point Segoe UI at 96 pixels per inch). I think this means windows7 thinks 1 inch of my monitor uses 96 pixels.
If I divide 1600 pixels by 12.20 inches (or 900 by 6,86) it results around 131,1.
What should be the expected DPI of the system? The horizontal one? the vertical one? Given this configuration a square would be seen as a rectangle in my screen? Am I missing something?
Original question has no sense now. Resolution and physical size follows the same 16:9 format now.
Now the question it bugs me is it seems the screen in reality has around 131 pixels per inch, but OS thinks it has 96 pixels by inch. If I tell a program to write a line of 1 inch how many pixels will be printed on the screen? 96 or 131? If I tell a program to write 131 pixels, and I put a ruler on the screen what would I measure?
Reason for edit: Sorry for any incovenience. I recheck the measures using a ruler and I did an error in the vertical measure.
