119
votes

I'm trying to make an array of structs where each struct represents a celestial body.

I don't have that much experience with structs, which is why I decided to try to use them instead of a whole bunch of arrays. However, I keep on running into numerous different errors. I've tried to implement the techniques that I've seen on various threads and on StackOverflow (such as Array of structs in C and C - initialize array of structs), however not all of them were applicable.

Further information for those who have read this far: I don't need any of this to be dynamic, I know/define the size of everything beforehand. I also need this to be a global array as I'm accessing this in several different methods which have defined arguments (i.e. GLUT methods).

This is how I'm defining the struct in my header:

struct body
{
    double p[3];//position
    double v[3];//velocity
    double a[3];//acceleration
    double radius;
    double mass;
};

I have a list of other global variables that I'm defining before I define the interior of the struct, and one of those is the array of this struct (basically, if I'm being too unclear in my fogged speak, the line below is above the stuff above):

struct body bodies[n];

Just so you know, n is something that I've legitimately defined (i.e. #define n 1).

I use this array in several different methods, but the easiest and least space consuming one is a simplified form of my main. Here I initialize all of the variables in each of the structs, just to set the variables for certain before I modify them in some way:

  int a, b;
 for(a = 0; a < n; a++)
 {
        for(b = 0; b < 3; b++)
        {
            bodies[a].p[b] = 0;
            bodies[a].v[b] = 0;
            bodies[a].a[b] = 0;
        }
        bodies[a].mass = 0;
        bodies[a].radius = 1.0;
 }

The current error that I'm facing is nbody.c:32:13: error: array type has incomplete element type where line 32 is where I'm making the array of the structs.

One last clarification, by header I mean the space above int main(void) but in the same *.c file.

7
Well, it works fine for me. Aren't you declaring struct body bodies[n]; before struct body {} declaration? - Jack
Note that using variable-length arrays can often cause mysterious bugs or crashes when the size of the array exceeds the program's stack size on your system (which is completely out of your control as a programmer). It is better to use malloc() for this sort of thing. - adrian
@adrian I think since it's a #defined value, it's not variable. It would be just the same as struct body bodies[1], or whatever the value of n is. - Redwolf Programs
@RedwolfPrograms ah sorry, I did not consider that. For the record, if n is a constant which can be determined at compile time you are probably safe. - adrian

7 Answers

117
votes
#include<stdio.h>
#define n 3
struct body
{
    double p[3];//position
    double v[3];//velocity
    double a[3];//acceleration
    double radius;
    double mass;
};

struct body bodies[n];

int main()
{
    int a, b;
     for(a = 0; a < n; a++)
     {
            for(b = 0; b < 3; b++)
            {
                bodies[a].p[b] = 0;
                bodies[a].v[b] = 0;
                bodies[a].a[b] = 0;
            }
            bodies[a].mass = 0;
            bodies[a].radius = 1.0;
     }

    return 0;
}

this works fine. your question was not very clear by the way, so match the layout of your source code with the above.

16
votes

So to put it all together by using malloc():

int main(int argc, char** argv) {
    typedef struct{
        char* firstName;
        char* lastName;
        int day;
        int month;
        int year;

    }STUDENT;

    int numStudents=3;
    int x;
    STUDENT* students = malloc(numStudents * sizeof *students);
    for (x = 0; x < numStudents; x++){
        students[x].firstName=(char*)malloc(sizeof(char*));
        scanf("%s",students[x].firstName);
        students[x].lastName=(char*)malloc(sizeof(char*));
        scanf("%s",students[x].lastName);
        scanf("%d",&students[x].day);
        scanf("%d",&students[x].month);
        scanf("%d",&students[x].year);
    }

    for (x = 0; x < numStudents; x++)
        printf("first name: %s, surname: %s, day: %d, month: %d, year: %d\n",students[x].firstName,students[x].lastName,students[x].day,students[x].month,students[x].year);

    return (EXIT_SUCCESS);
}
13
votes

Another way of initializing an array of structs is to initialize the array members explicitly. This approach is useful and simple if there aren't too many struct and array members.

Use the typedef specifier to avoid re-using the struct statement everytime you declare a struct variable:

typedef struct
{
    double p[3];//position
    double v[3];//velocity
    double a[3];//acceleration
    double radius;
    double mass;
}Body;

Then declare your array of structs. Initialization of each element goes along with the declaration:

Body bodies[n] = {{{0,0,0}, {0,0,0}, {0,0,0}, 0, 1.0}, 
                  {{0,0,0}, {0,0,0}, {0,0,0}, 0, 1.0}, 
                  {{0,0,0}, {0,0,0}, {0,0,0}, 0, 1.0}};

To repeat, this is a rather simple and straightforward solution if you don't have too many array elements and large struct members and if you, as you stated, are not interested in a more dynamic approach. This approach can also be useful if the struct members are initialized with named enum-variables (and not just numbers like the example above) whereby it gives the code-reader a better overview of the purpose and function of a structure and its members in certain applications.

12
votes

I think you could write it that way too. I am also a student so I understand your struggle. A bit late response but ok .

#include<stdio.h>
#define n 3

struct {
    double p[3];//position
    double v[3];//velocity
    double a[3];//acceleration
    double radius;
    double mass;
}bodies[n];
8
votes

move

struct body bodies[n];

to after

struct body
{
    double p[3];//position
    double v[3];//velocity
    double a[3];//acceleration
    double radius;
    double mass;
};

Rest all looks fine.

1
votes

That error means that the compiler is not able to find the definition of the type of your struct before the declaration of the array of structs, since you're saying you have the definition of the struct in a header file and the error is in nbody.c then you should check if you're including correctly the header file. Check your #include's and make sure the definition of the struct is done before declaring any variable of that type.

1
votes

Solution using pointers:

#include<stdio.h>
#include<stdlib.h>
#define n 3
struct body
{
    double p[3];//position
    double v[3];//velocity
    double a[3];//acceleration
    double radius;
    double *mass;
};


int main()
{
    struct body *bodies = (struct body*)malloc(n*sizeof(struct body));
    int a, b;
     for(a = 0; a < n; a++)
     {
            for(b = 0; b < 3; b++)
            {
                bodies[a].p[b] = 0;
                bodies[a].v[b] = 0;
                bodies[a].a[b] = 0;
            }
            bodies[a].mass = 0;
            bodies[a].radius = 1.0;
     }

    return 0;
}