I define an operator as follows:
:- op(500, xfx, =>).
When I try something like:
assert(a => b).
Prolog raises an error that says 'No permission to modify static_procedure (=>)/2'.
Any solution?
You must have meant another symbol in place of (=>)/2
. Probably (->)/2
which is a control construct that cannot be modified.
Welcome to SWI-Prolog (Multi-threaded, 32 bits, Version 6.1.3-116-gf1c7e06) ... ?- asserta((a -> b)). ERROR: asserta/1: No permission to modify static procedure `(->)/2' ERROR: Defined at /opt/gupu/pl-devel/lib/swipl-6.1.3/boot/init.pl:194 ?- op(500, xfx, =>). true. ?- asserta(a => b). true.