142
votes

Is there a way I can do a sleep in JavaScript before it carries out another action?

Example:

 var a = 1+3;
 // Sleep 3 seconds before the next action here
 var b = a + 4;
13

13 Answers

149
votes

You can use setTimeout to achieve a similar effect:

var a = 1 + 3;
var b;
setTimeout(function() {
    b = a + 4;
}, (3 * 1000));

This doesn't really 'sleep' JavaScript—it just executes the function passed to setTimeout after a certain duration (specified in milliseconds). Although it is possible to write a sleep function for JavaScript, it's best to use setTimeout if possible as it doesn't freeze everything during the sleep period.

67
votes

In case you really need a sleep() just to test something. But be aware that it'll crash the browser most of the times while debuggin - probably that's why you need it anyway. In production mode I'll comment out this function.

function pauseBrowser(millis) {
    var date = Date.now();
    var curDate = null;
    do {
        curDate = Date.now();
    } while (curDate-date < millis);
}

Don't use new Date() in the loop, unless you want to waste memory, processing power, battery and possibly the lifetime of your device.

16
votes

ECMAScript 6 version, using generators with yield for "code blocking":

Because the original question was posted seven years ago, I didn't bother answering with the exact code, because it's just way too easy and already answered. This should help in more complicated problems, like if you need at least two sleeps, or if you are planning to sequence asynchronous execution. Feel free to modify it to fit your needs.

let sleeptime = 100
function* clock()
{
    let i = 0
    while( i <= 10000 )
    {
        i++
        console.log(i); // actually, just do stuff you wanna do.
        setTimeout(
            ()=>
            {
                clk.next()
            }
            , sleeptime
        )
        yield
    }
}

let clk = clock()
clk.next()

function*

() => arrow function

You can also chain events via Promises:

function sleep(ms)
{
    return(
        new Promise(function(resolve, reject)
        {
            setTimeout(function() { resolve(); }, ms);
        })
    );
}


sleep(1000).then(function()
{
    console.log('1')
    sleep(1000).then(function()
    {
        console.log('2')
    })
})

Or much simpler and a less fancy way would be

function sleep(ms, f)
{
    return(
        setTimeout(f, ms)
    )
}


sleep(500, function()
{
    console.log('1')
    sleep(500, function()
    {
        console.log('2')
    })
})
console.log('Event chain launched')

If you're just waiting for some condition to happen you can wait like this

function waitTill(condition, thenDo)
{
    if (eval(condition))
    {
        thenDo()
        return
    }

    setTimeout(
        ()    =>
        {
            waitTill(condition, thenDo)
        }
        ,
        1
    )
}

x=0

waitTill(
    'x>2 || x==1'
    ,
    ()    =>
    {
        console.log("Conditions met!")
    }
)

// Simulating the change
setTimeout(
    () =>
    {
        x = 1
    }
    ,
    1000
)
12
votes

2018 Update

The latest Safari, Firefox and Node.js are now also supporting async/await/promises.

Using async/await/Promises:

(As of 1/2017, supported on Chrome, but not on Safari, Internet Explorer, Firefox, Node.js)

'use strict';

function sleep(ms) {
  return new Promise(res => setTimeout(res, ms));
}

let myAsyncFunc = async function() {
  console.log('Sleeping');
  await sleep(3000);
  console.log('Done');
}

myAsyncFunc();

2017 Update

JavaScript has evolved since this question was asked and now has generator functions, and the new async/await/Promise is being rolled out. Below there are two solutions, one with generator function that will work on all modern browsers, and another, using the new async/await that is not yet supported everywhere.

Using a generator function:

'use strict';

let myAsync = (g) => (...args) => {
    let f, res = () => f.next(),
        sleep = (ms) => setTimeout(res, ms);
    f = g.apply({sleep}, args); f.next();
};

let myAsyncFunc = myAsync(function*() {
    let {sleep} = this;
    console.log("Sleeping");
    yield sleep(3000);
    console.log("Done");
});

myAsyncFunc();

Pay attention to the fact that both these solutions are asynchronous in nature. This means that the myAsyncFunc (in both cases) will return while sleeping.

It is important to note that this question is different than What is the JavaScript version of sleep()? where the requestor is asking for real sleep (no other code execution on the process) rather than a delay between actions.

3
votes

If you want less clunky functions than setTimeout and setInterval, you can wrap them in functions that just reverse the order of the arguments and give them nice names:

function after(ms, fn){ setTimeout(fn, ms); }
function every(ms, fn){ setInterval(fn, ms); }

CoffeeScript versions:

after = (ms, fn)-> setTimeout fn, ms
every = (ms, fn)-> setInterval fn, ms

You can then use them nicely with anonymous functions:

after(1000, function(){
    console.log("it's been a second");
    after(1000, function(){
        console.log("it's been another second");
    });
});

Now it reads easily as "after N milliseconds, ..." (or "every N milliseconds, ...")

3
votes

Another way to do it is by using Promise and setTimeout (note that you need to be inside a function and set it as asynchronous with the async keyword) :

async yourAsynchronousFunction () {

    var a = 1+3;

    await new Promise( (resolve) => {
        setTimeout( () => { resolve(); }, 3000);
    }

    var b = a + 4;

}
2
votes

Here's a very simple way to do it that 'feels' like a synchronous sleep/pause, but is legit js async code.

// Create a simple pause function
const pause = (timeoutMsec) => new Promise(resolve => setTimeout(resolve,timeoutMsec))

async function main () {
    console.log('starting');
    // Call with await to pause.  Note that the main function is declared asyc
    await pause(3*1000)
    console.log('done');
}
2
votes

You can use plain javascript, this will call your function/method after 5 seconds:

setTimeout(()=> { your_function(); }, 5000);
1
votes

function delayer(ms){
  return new Promise((resolve, reject)=>{
    setTimeout(()=>{
      resolve();
    }, ms)
  })
}

async function myFunction(){  // Function Must be async.
  console.log("First Console")
  await delayer(2000);    // This Will Stop The Code For 2 Seconds
  console.log("Second Console")
}


myFunction()
0
votes

There are several ways to solve this problem. If we use the setTimeout function, let's get to know it first. This function has three parameters: function or code, delay (in milliseconds) and the parameters. Since the function or code parameter is required, the others are optional. Once you have not entered the delay, it will be set to zero.

For more details about the setTimeout() go to this link.

Simplified version:

var a = 1 + 3;
var b;
console.log('a = ' + a);
setTimeout(function(){ 
    b = a + 4; 
    console.log('b = ' + b);
}, 1000);

output:
a = 4
24       --> Number identifier of the list of active timeouts
b = 8


Using the parameter pass:

var a = 1 + 3;
var b;
console.log('a = ' + a);
setTimeout(myFunction, 1000, a);

function myFunction(a)
{
    var b = a + 4;
    console.log('b = ' + b);
}

output:
a = 4
25       --> Number identifier of the list of active timeouts
b = 8



Browser Support:

Chrome     Firefox     Edge     Safari     Opera
1.0        1.0         4.0      1.0        4.0
0
votes

This is my model that shows how to "sleep" or "DoEvents" in javascript using a generator function (ES6). Commented code:

<html>
<head>
<script>
  "use strict"; // always
  // Based on post by www-0av-Com https://stackguides.com/questions/3143928
  // https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/function*
  var divelt, time0, globaln = 0; // global variables
  var MainGenObj = Main(); // generator object = generator function()
window.onload = function() {
  divelt = document.getElementsByTagName("body")[0]; // for addline()
  addline("typeof Main: " + typeof Main);
  addline("typeof MainDriver: " + typeof MainDriver);
  addline("typeof MainGenObj: " + typeof MainGenObj);
  time0 = new Date().valueOf(); // starting time ms
  MainDriver(); // do all parts of Main()
}
function* Main() { // this is "Main" -- generator function -- code goes here
  // could be loops, or inline, like this:

  addline("Part A, time: " + time() + ", " + ++globaln); // part A
  yield 2000;                    // yield for 2000 ms (like sleep)

  addline("Part B, time: " + time() + ", " +  ++globaln); // part B
  yield 3000;                    // yield for 3000 ms (or like DoEvents)

  addline("Part Z, time: " + time() + ", " +  ++globaln); // part Z (last part)
  addline("End, time: " + time());
}
function MainDriver() { // this does all parts, with delays
  var obj = MainGenObj.next(); // executes the next (or first) part of Main()
  if (obj.done == false) { // if "yield"ed, this will be false
    setTimeout(MainDriver, obj.value); // repeat after delay
  }
}
function time() { // seconds from time0 to 3 decimal places
  var ret = ((new Date().valueOf() - time0)/1000).toString();
  if (ret.indexOf(".") == -1) ret += ".000";
  while (ret.indexOf(".") >= ret.length-3) ret += "0";
  return ret;
}
function addline(what) { // output
  divelt.innerHTML += "<br />\n" + what;
}
</script>
</head>
<body>
<button onclick="alert('I\'m alive!');"> Hit me to see if I'm alive </button>
</body>
</html>
0
votes

Try this function:

const delay = (ms, cb) => setTimeout(cb, ms)

Here is how you use it:

console.log("Waiting for 5 seconds.")
delay(5000, function() {
  console.log("Finished waiting for 5 seconds.")
})

Or go promise style:

const delay = ms => new Promise(resolve => {
    setTimeout(resolve, ms)
})

Here's a demo.

0
votes

Here's a re-write and a demo of a Promise-based sleep() using call to setTimeout(). It also demoes a regular call to setTimeout(). It's self-explanatory once you run it. :)

function sleep(ms) {
    return new Promise(resolve => setTimeout(() => resolve(), ms))
}

console.log("Synchronous call 1");
sleep(4000)
.then(() => console.log("Asynchronous call 1"));
sleep(2000)
.then(() => console.log("Asynchronous call 2"));
console.log("Synchronous call 2");
sleep(3000)
.then(() => console.log("Asynchronous call 3"));
console.log("Synchronous call 3");
sleep(5000)
.then(() => console.log("Asynchronous call 4"))
.then(sleep(7000)
.then(()=>console.log("Asynchronous call 5")))
console.log("Synchronous call 4");
setTimeout(() => {console.log("Asynchronous call 6")}, 8000);
console.log("Synchronous call 5");

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