python - How to remove items from list and make items join

0
votes

Hi i have a list wich has number but because its appended to a list using for loop it has '\n' and I don't know how to remove it.

the list looks like this

['3', '7', '4', '5', '5', '9', '2', '2', '7', '\n', '4', '3', '7', '1', '5', '9', '4', '3', '0', '\n', '3', '7', '2', '4', '1', '0', '2', '7', '5', '\n', '7', '8', '4', '5', '1', '6', '2', '5', '7', '\n', '2', '8', '0', '6', '6', '1', '1', '2', '3', '\n', '9', '3', '5', '6', '8', '3', '8', '7', '1', '\n', '6', '7', '5', '5', '4', '7', '4', '8', '6']

I want to remove ' ' and '\n' so it would look like this

[374559227,437159430,372410275,784516257,280661123,935683871,675547486]
3
pythonpython-3.xlist
Where does that weird list come from to begin with? Can you read it differently somehow so you don't need to post-process it like this…? – deceze♦
split the list by '\n', turn each number to an int and join them. – Craicerjack

3 Answers

4
votes

Join to a string and split the newlines:

l = [
    '3', '7', '4', '5', '5', '9', '2', '2', '7', '\n', '4', '3', '7', '1', '5',
    '9', '4', '3', '0', '\n', '3', '7', '2', '4', '1', '0', '2', '7', '5', '\n',
    '7', '8', '4', '5', '1', '6', '2', '5', '7', '\n', '2', '8', '0', '6', '6',
    '1', '1', '2', '3', '\n', '9', '3', '5', '6', '8', '3', '8', '7', '1', '\n',
    '6', '7', '5', '5', '4', '7', '4', '8', '6'
]
print([int(x) for x in ''.join(l).split('\n')])
>>> [374559227, 437159430, 372410275, 784516257, 280661123, 935683871, 675547486]
2
votes

You can use itertools.groupby:

>>> from itertools import groupby
>>> lst = ['3', '7', '4', '5', '5', '9', '2', '2', '7', '\n', '4', '3', '7', '1', '5', '9', '4', '3', '0', '\n', '3', '7', '2', '4', '1', '0', '2', '7', '5', '\n', '7', '8', '4', '5', '1', '6', '2', '5', '7', '\n', '2', '8', '0', '6', '6', '1', '1', '2', '3', '\n', '9', '3', '5', '6', '8', '3', '8', '7', '1', '\n', '6', '7', '5', '5', '4', '7', '4', '8', '6']    
>>> [int(''.join(digits)) for is_number, digits in groupby(lst, lambda x: x != '\n') if is_number]
[374559227, 437159430, 372410275, 784516257, 280661123, 935683871, 675547486]
0
votes

You can use reduce function

from functools import reduce
lst = ['3', '7', '4', '5', '5', '9', '2', '2', '7', '\n', '4', '3', '7', '1', '5', '9', '4', '3', '0', '\n', '3', '7', '2', '4', '1', '0', '2', '7', '5', '\n', '7', '8', '4', '5', '1', '6', '2', '5', '7', '\n', '2', '8', '0', '6', '6', '1', '1', '2', '3', '\n', '9', '3', '5', '6', '8', '3', '8', '7', '1', '\n', '6', '7', '5', '5', '4', '7', '4', '8', '6']
lst_result = [int(n) for n in reduce(lambda x, y: f"{x}{y}", lst).split('\n')]

Output:

[374559227, 437159430, 372410275, 784516257, 280661123, 935683871, 675547486]